The average daily metabolic rate for captive animals from weasels to elk can be expressed as a function of mass byr = 140.2m0.75,where m is the mass of the animal (in kilograms) and r is the metabolic rate (in kcal per day).

a) Use your sketching and writing skills to explain the relationship between metabolic rate (M) and body weight (W): M = aWb b) Based on your answer to question a), generate a new graph to explain how the exponent b in the allometric relationship changes between different groups of animals; and what would happen graphically if M is expressed per gram of body weight: M/W =aW(b-1)

In active muscle cells, the pO2 is about 10 torr at the cell surface and 1 torr at the mitochondria(the organelles where oxidative metabolism occurs). Calculate the percentage of bound oxygentransported to the mitochondria of muscle cells by myoglobin (KD = 2 torr).

If the enzyme lactase has a Vo of 0.40 mM per minute when [S] = 1.25 mM, and a Vo of 1.0 mM per minute when [S] = 5.0 mM, what is its Vmax, Km and the slope on a linewver-burk plot?

Calculate the free energy change for glucose entry into cells when the extracellular concentration is 4.5 mM and the intracellular concentration is 2.1 mM at 37oC. Express your answer in kJ/mol.

make a Gibbs free energy graph as free energy as y-axis a for the transition state as a function of [Gdn HCl] (x-axis) with a line of best fit

Body Weight: 58.5kg   Height: 170cm    Wrist Circumference: 15.2cm       Height-Wrist Circumference Ration = 170/15.2                                                                = 11.18      Frame size = Small frame    Desirable Body Weight Range = 135 - 143    Body Mass Index (BMI): 20.2   Arm Span: 172cm  Percent Difference = {1 - (172/170)} x 100%                                    = -1.1%   Fat Mass (kg, from skin-fold measurement) = 12.00 Fat-free Mass (kg, from skin-fold measurement) = 46.5 Percent Body Fat (from skin-fold measurement) = 20.51% Percent Fat-free Mass (from skin-fold measurement) = 79.49 Percent Body Fat (from BIA) = 17.5% Percent Fat-free Mass (from BIA) = 82.5% Mid-Arm Circumference (MAC): 25 cm Mid-Arm Muscle Circumference (MAMC) = 22.94958 cm   based on the above measurement, comment on the health status

Consider the following equilibrium at 298 K. R=8.314 J/K-mol Acetyl-CoA + Oxaloacetate + H20 Citrate + COASH + H* Which one of the following is the correct value for K'eg ifAG" = -32.2 kJ/mol? O 1.11 0.987 1.01 x 10-13 13.0 9.92 x 1012 2480 4.42 x 105 2.27 x 10-6 1.01 -2480 2.56 -13.0 1.08 -0.0130 0.0130 0.926