The auxiliary equation of  of  y'''-4y''-4y'+16y=0  is r^(3)-4r^(2)-4r+16=0  . The auxiliary equation has a root in the interval [3,6].   Let f(r)=r^(3) -4r^(2)-4r+16 , so that the roots of the auxiliary equation can be determined by solving f(r)=0 .   Then, applying four iterations of the Bisection Method to f(r) , using the initial approximations r1=3  and r2=6 , gives the following approximations for the root in [3,6]:       r3^(1)=    r3^(2)=   r3^(3)=    r3^(4)=

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