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The area of a rectangle is m² + 2m - 80. If the length is (m + 10), what is the width? A= m^2+2m-80 L= (m+10) W= m-8 Factoring m^2+2m-80 = m^2+10m-8m-80 m(m-8)+10(m-8) (m+10)(m-8) = The width of the rectangle is (m-8). -80 2 10

The area of a rectangle is m² + 2m - 80. If the length is (m + 10), what is the width? A= m^2+2m-80 L= (m+10) W= m-8 Factoring m^2+2m-80 = m^2+10m-8m-80 m(m-8)+10(m-8) (m+10)(m-8) = The width of the rectangle is (m-8). -80 2 10

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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  • Identify the process used when finding width.

for example when we find area we use (x+a)(a+b)=x^2+ax+bx+ab

x^2+(a+b)x+ab

The area of a rectangle is m² + 2m - 80. If the length is (m + 10), what is the width? A= m^2+2m-80 L= (m+10) W= m-8 Factoring m^2+2m-80 m^2+10m-8m-80 m(m-8)+10(m-8) = (m+10)(m-8) The width of the rectangle is (m-8). ******** -80 2 10 *******
Transcribed Image Text:The area of a rectangle is m² + 2m - 80. If the length is (m + 10), what is the width? A= m^2+2m-80 L= (m+10) W= m-8 Factoring m^2+2m-80 m^2+10m-8m-80 m(m-8)+10(m-8) = (m+10)(m-8) The width of the rectangle is (m-8). ******** -80 2 10 *******
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