The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 66 minutes and a standard deviation of 14 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X - N( b. Find the probability that a randomly selected person at the hot springs stays longer then 77 minutes. c. The park service is considering offering a discount for the 8% of their patrons who spend the least time at the hot springs. What is the longest amount of time a patron can spend at the hot springs and still receive the discount? minutes.

Private nonprofit four-year colleges charge, on average, $27,363 per year in tuition and fees. The standard deviation is $6,865. Assume the distribution is normal. Let X be the cost for a randomly selected college. Round all answers to 4 decimal places where possible.b. Find the probability that a randomly selected Private nonprofit four-year college will cost less than 25,876 per year. ________ - 0.4129 is wrongc. Find the 68th percentile for this distribution. $ _______ (Round to the nearest dollar.) - 30573.752 is wrong

pr The lengths of pregnancies are normally distributed with a mean of 269 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not premature. /2 pr Click to view page 1 of the table. Click to view page 2 of the table. /2 a. The probability that a pregnancy will last 308 days or longer is (Round to four decimal places as needed.) pr b. Babies who are born on or before 12 days are considered premature. (Round to the nearest integer as needed.) /2 12 uc /2 12 or /2 or (2 Enter your answer in each of the answer boxes.

Yellow one is tab #1

Provide an appropriate response. Use the Standard Normal Table to find the probability. IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An individual's IQ score is found to be 90. Find the z-score corresponding to this value. OA. -1.33 OB. 1.33 OC. 0.67 O D. -0.67 C

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need help with this, need answers for  A B C D E F thanks!

SubPArt. Pls answer the rest

Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 2) The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 5478 .5517 .5557 .5596 ,5636 ,5675 .5714 .5753 0.2 .5793 .5832 5871 5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.5 .6915 6950 .6985 7019 .7054 .7088 7123 7157 .7190 .7224 0.6 .7257 .7291 7324 7357 7389 7422 7454 7486…