The actual tracking weight of a stereo cartridge that is set to track at 3g on a particular changer can beregarded as a continuous random variable X with the following pdf.Į k(1 – (x – 3)² ),2

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Answered: The actual tracking weight of a stereo…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The table below shows the probability distribution function of the number of accidents (X) occur in a day by taxis belonging to a taxi company. x 0 1 2 3 4 P(X = x) 0.5 0.15 0.05 2k k (a) Find the value of k.(b) Find the expected value and standard deviation of the number of accidents (X) occurring in a day.(c) Assume the net profit ($), Y, of the taxi company in a day is given by Y = 10000 – 4000X. Find theexpected value, variance, and standard deviation of the net profit of the taxi company in a day.(d) What is the maximum profit the company earn in a day? What is the corresponding probability?(e) What is the probability that the company loses money in a day?(f) Find the probability that there are exactly 3 days that the company loses money in a week (7 days).
please help
D=19
parts of question 7. solve A-E A. Compute P(X = 3) for n = 5, p = 1 B. Ken is a waiter at a restaurant. His customers tip 15% or more 80% of the time. Find the probability that four of the next six customers will tip 15% or more? C. Find the z-score if x = 2.65, mean = 0, σσ = 1.0. D. An IQ test has a mean of 100 and standard deviation of 15. Find what percentile is someone who scored a 122 on an IQ score? E. A normal distribution has a mean of 168 and a standard deviation of 10. Find the percentage of scores that fall between 155 and 169.
Please i needs these two. Help me
Can someone explain it to me why I’m getting wrong answer??!!!
4. As fallen trees lie on the forest floor they slowly decay. Will the amount of light present have an impact on the rate of decay? In the following table x is a random variable representing the remaining percentage of total mass of a log after it was exposed to the elements for three weeks while y represents the numbers of hours of direct sunlight the log received each day. X 0.60 .70 .65 .82 .87 y 1.0 2.3 3.0 4.0 4.5 (a) Plot a scatter diagram of the data. Remember to label your axes appropriately and choose a consistent scale. (b) Based on a scatter diagram, would you estimate the correlation coefficient to be positive, close to zero, or negative? Please circle one of the following choices: A. Positive B. Close to zero C. Negative (c) Interpret your results from parts (a) and (b). 16 tv
Find the marginal probability of X = 1. %3D Y 1 3 5 1 0.05 0.05 0.05 0.1 0.2 3 0.1 0.35 0.1 Round your answer to 3 decimal places. 2.
Q.7 For an exponential distribution fx(x; p) = (ue H, x20 %3D e. w. where u > 0 Write (Don't derive) (a) Mean (expected value), i.e. E(X). (b) Standard deviation, i.e. S.D. (X). (c) Moment generating function, i.e. Mx(t). (d) Cumulative distribution function (cdf), Fx(x). of Nizv
This was what WAS given please helpppp
Let X be the total amount saved in dollars at the cash register. The pdf of X is given by: Value of X 20 28 40 50 58 70 probability 0.36 0.21 0.24 0.1225 0.0175 0.03 .0175 0.0025 Before I make the purchase, you would place my chance of saving $20 at 24%. Suppose you approach me after I pay for my items and ask: "Did you save any money?" If I answer "no", then you know I didn't save $20 and thus the chance of saving $20 changes from the unconditional chance 24% to the conditional chance 0%. However, if I answer "yes" my chance of saving $20 would get higher. What would be the conditional chance of saving $20 if you knew I got a discount? Mathematically, we seek: P(X = 20|X > 0 ). Even though it looks weird, it is just a conditional probability. Find it. P(X = 20|X > 0) = P(X = 20 and X > 0) / P(X > 0) = Hint: P(X = 20 and X > 0) be read off the table by identifying possible values where the event (X = 20 and X > 0) is true, don't use the multiplication rule. Do not round, express your…

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