MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Fill in missing values in the following statements. The distribution of the lengths of long-stemmed roses is mound – shaped and symmetric with the mean stem length of 16 inches and standard deviation of 3 inches. According Empirical rule _______ percent of the long-stemmed roses have the lengths between 10 inches and 22 inches. _______ percent of long-stemmed roses have the lengths larger than 19 inches. _______ percent of long-stemmed roses have the lengths between 10 inches and 19 inches.arrow_forwardThe Acme Company manufactures widgets. The distribution of widget weights is bell shaped. The widget have a mean of 40 ounces and a standard deviation of 10 ounces. What percentage of the widget weights lie between 20 and 70 ounces?arrow_forwardThe GMAC Insurance company reported that the mean score on the National Drivers Test was 77.8 with a standard deviation of 2.5 points. The test scores are approximately bell-shaped. Approximately 68% of all test scores were between two values A and B. What is the value of A? Write only a number as your answer. Round to one decimal place.arrow_forward
- Subject: algberaarrow_forwardThe mean height of Americans in 1776 was 67 inches with a standard deviation of 3 inches. George Washington is believed to have been 6 ft 2 inches tall, or 74 inches. Between what two heights (in inches) do 68% of the heights fall? a.61 to 70 b.61 to 73 c.64 to 70arrow_forwardIn an Algebra class, the scores on a test are normally distributed. The middle 68% of the scores fall between 71 and 83. What are the mean and standard deviation for this data?arrow_forward
- A survey collected the data below. x 26 4 16 12 20 The mean is 15.6. Calculate the deviation of x=16 ?arrow_forwardI was wondering if these answers are correct. Explain. A study by Quadrant Information Services commissioned by Insure.com calculated auto insurance rates for each of the 50 states; and as a result, the average annual rate for the United States was $1,317. Suppose annual rates of auto insurance in the United States are normally distributed with a standard deviation of $324. According to MoneyGeek, a state minimum auto insurance policy in Florida costs an average of $1123 per year and the average cost of full coverage car insurance in Florida is $2208. What percentage of policies cost less than the Florida state minimum policy of $1123? z = (x - mu) / sigma z = (1123-1317)/324 z= -0.59876543 P-value from Z-Table: P(x<1123) = 0.27466 The answer is less than I expected. After using a z-table to determine the score it results in 27% of policies that are less than the minimum policy of 1123. What percentage of auto insurance rates would be less than $1,200? z = (x - mu) / sigma…arrow_forwardStudents in a class took a test whose results were normally distributed. The mean score was an 81 and the standard deviation was 4.5. What score is at the 83rd percentile (round to the nearest whole number.) a.84 b.83 c.85 d.86arrow_forward
- Use a calculator or computer software to generate a normal quantile plot for the data in the accompanying table. Then determine whether the data come from a normally distributed population. Click the icon to view the data set. Generate a normal quantile plot for the data. Choose the correct graph below. O A. 3.00- 2.00- 1.00- 0.00- -1.00- -2.00- -3.00- 0 100 200 300 400 500 X Value B. 3.00- 2.00- 1.00- 0.00- -1.00- -2.00- -3.00+ 0 100 200 300 400 500 X Value Determine whether the data come from a normally distributed population. Choose the correct answer below. Data table A. The distribution is normal. The points are reasonably close to a straight line and donot show a systematic pattern that is not a straight-line pattern. B. The distribution is normal. The points show a systematic pattern that is not a straight-line pattern. C. The distribution is not normal. The points show a systematic pattern that is not a straight-line pattern. D. The distribution is not normal. The points are…arrow_forwardYou want to know the percentage of utility companies that earned revenue less than 67 million dollars. If the mean revenue was 50 million dollars and the data has a standard deviation of 7 million, find the percentage. Assume that the distribution is normal. Round your answer to the nearest hundredth.arrow_forwardFind the indicated IQ score. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. The indicated IQ score, x, is (Round to one decimal place as needed.) X 0.75 0arrow_forward
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