MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Poplar Weights (kg) and Bonferroni Results Poplar Weights (kg) and Bonferroni Results No Treatment 1.208 0.568 0.555 0.132 1.302 U. VII sprayu Duen results on US (1) TREATMENT 1.00 With a P-value of , there With a P-value of, there With a P-value of, there (Round to three decimal places as needed.) V Ho: H₂: Determine the null and alternative hypotheses. I this Fertilizer 0.937 0.874 0.461 0.582 1.032 DUNIBITON results. Bonferroni Results Print View an example Mean (J) TREATMENT Difference (I-J) Std. Error 2.00 3.00 4.00 Irrigation 0.067 0.658 0.104 0.817 0.942 Get more help. a significant difference between the No Treatment and Fertilizer groups. a significant difference between the No Treatment and Irrigation groups. a significant difference between the No Treatment and Fertilizer and Irrigation groups. -0.0242 0.2354 -0.8454 c. Let H. H₂, H3, and 4 represent the mean amount of the no treatment, fertilizer, irrigation, and fertilizer and irrigation groups, respectively. Use the Bonferroni test procedure with a 0.10 significance level to test for a significant difference between the mean amount of the irrigation treatment group and the group treated with both fertilizer and irrigation. Identify the test statistic and the P-value. What do the results indicate? Ho: My H₂Pg "He H₁: At least one of the four population means is different from the others Done Determine the test statistic The test statistic is (Round to two decimal places as needed) Determine the P-value. I The P-value is (Round to three decimal places as needed.) What is the conclusion for this hypothesis test at a 0.10 significance level? Fertilizer and Irrigation 0.845 1.783 1.471 2.249 1.644 a. Use a 0.10 significance level to test the claim that the different treatments result in the same mean weight Determine the null and alternative hypotheses The test statistic is (Round to two decimal places as needed.). Find the P-value. The P-value is (Round to three decimal places as needed.) What do the results indicate at a 0.10 significance level? A. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar Sig. 0.26983 1.000 0.26983 1.000 0.26983 0.039 The accompanying data are the weights (kg) of poplar trees that were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Also shown are partial results from using the Bonferoni test with the sample data. Complete parts (a) through (c) Click the icon to view the data table of the poplar weights and the Bonferroni results. - X OA Fall to reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight B. Reject H₂. There is sufficient evidence to wamant rejection of the claim that the four different treatments yield the same mean poplar weight OC. Fal to reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight OD. Reject Hg. There is insufficient evidence to wamant rejection of the claim that the four different treatments yield the same mean poplar weight What do the displayed Bonferroni results tell us? - ght. Next
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Transcribed Image Text:Poplar Weights (kg) and Bonferroni Results Poplar Weights (kg) and Bonferroni Results No Treatment 1.208 0.568 0.555 0.132 1.302 U. VII sprayu Duen results on US (1) TREATMENT 1.00 With a P-value of , there With a P-value of, there With a P-value of, there (Round to three decimal places as needed.) V Ho: H₂: Determine the null and alternative hypotheses. I this Fertilizer 0.937 0.874 0.461 0.582 1.032 DUNIBITON results. Bonferroni Results Print View an example Mean (J) TREATMENT Difference (I-J) Std. Error 2.00 3.00 4.00 Irrigation 0.067 0.658 0.104 0.817 0.942 Get more help. a significant difference between the No Treatment and Fertilizer groups. a significant difference between the No Treatment and Irrigation groups. a significant difference between the No Treatment and Fertilizer and Irrigation groups. -0.0242 0.2354 -0.8454 c. Let H. H₂, H3, and 4 represent the mean amount of the no treatment, fertilizer, irrigation, and fertilizer and irrigation groups, respectively. Use the Bonferroni test procedure with a 0.10 significance level to test for a significant difference between the mean amount of the irrigation treatment group and the group treated with both fertilizer and irrigation. Identify the test statistic and the P-value. What do the results indicate? Ho: My H₂Pg "He H₁: At least one of the four population means is different from the others Done Determine the test statistic The test statistic is (Round to two decimal places as needed) Determine the P-value. I The P-value is (Round to three decimal places as needed.) What is the conclusion for this hypothesis test at a 0.10 significance level? Fertilizer and Irrigation 0.845 1.783 1.471 2.249 1.644 a. Use a 0.10 significance level to test the claim that the different treatments result in the same mean weight Determine the null and alternative hypotheses The test statistic is (Round to two decimal places as needed.). Find the P-value. The P-value is (Round to three decimal places as needed.) What do the results indicate at a 0.10 significance level? A. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar Sig. 0.26983 1.000 0.26983 1.000 0.26983 0.039 The accompanying data are the weights (kg) of poplar trees that were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Also shown are partial results from using the Bonferoni test with the sample data. Complete parts (a) through (c) Click the icon to view the data table of the poplar weights and the Bonferroni results. - X OA Fall to reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight B. Reject H₂. There is sufficient evidence to wamant rejection of the claim that the four different treatments yield the same mean poplar weight OC. Fal to reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight OD. Reject Hg. There is insufficient evidence to wamant rejection of the claim that the four different treatments yield the same mean poplar weight What do the displayed Bonferroni results tell us? - ght. Next
this ✓ The accompanying data are the weights (kg) of poplar trees that were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Also shown are partial results from using the Bonferroni test with the sample data. Complete parts (a) through (c). Click the icon to view the data table of the poplar weights and the Bonferroni results. a. Use a 0.10 significance level to test the claim that the different treatments result in the same mean weight. Determine the null and alternative hypotheses. Ho H₁ H₂ H3 H4 H₁: At least one of the four population means is different from the others Determine the test statistic. The test statistic is. (Round to two decimal places as needed.) Determine the P-value. I The P-value is. (Round to three decimal places as needed.) What is the conclusion for this hypothesis test at a 0.10 significance level? OA. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. OB. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. OC. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. OD. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. b. What do the displayed Bonferroni results tell us? — View an example Get more help. 0 FS 000 000 F4 F5 MacBook Air *** F6 & F7 * FB 1 F9 F10 FI - Next
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Transcribed Image Text:this ✓ The accompanying data are the weights (kg) of poplar trees that were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Also shown are partial results from using the Bonferroni test with the sample data. Complete parts (a) through (c). Click the icon to view the data table of the poplar weights and the Bonferroni results. a. Use a 0.10 significance level to test the claim that the different treatments result in the same mean weight. Determine the null and alternative hypotheses. Ho H₁ H₂ H3 H4 H₁: At least one of the four population means is different from the others Determine the test statistic. The test statistic is. (Round to two decimal places as needed.) Determine the P-value. I The P-value is. (Round to three decimal places as needed.) What is the conclusion for this hypothesis test at a 0.10 significance level? OA. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. OB. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. OC. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. OD. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. b. What do the displayed Bonferroni results tell us? — View an example Get more help. 0 FS 000 000 F4 F5 MacBook Air *** F6 & F7 * FB 1 F9 F10 FI - Next
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