The 5W motor operated for 10s and pulled the cable by 2m. The cable is connected to a single fixed followed by a single movable pulley. Another cable connects the movable pulley and an initially stationary Block A (4kg) on a horizontal Surface X. Between Block A and the horizontal Surface X, Hstart=0.15 and μslide = 0.1. Just after 0.1s, Block A had an elastic collision with Block B (2kg) on a horizontal Surface Y with negligible friction. 1) Calculate the force experienced by the cable, that is connected to Block A. 2) Calculate the net force on Block A, before the collision. 3) Calculate the velocity of Block A, just before collision. 4) Calculate the velocity of Block B, after collision. 5) Suggest how to increase the velocity of Block B by 50%. A Surface X B Surface Y Motor G

Can tutor be more clearly on why it need to times 1.5 and how to make use the formula to make it increase the velocity of Block B by 50%

For questions 4)r Calculate the velocity of Block B, after collision.

can tutor use m1u1 + m2u2 = m1v1 + m2v2 and u1 – u2 = v2 – v1 to do ? as it is a elastic collision and my lecture need us to use this two equation for elastic collision to solve the velocity 

can u explain questions Q3 more clearly and am I able to apply the momentum formula ? 

I do not understand the questiona 1 Calculation of force experience d by cable connected to block A, why using equation P=F/t x s instead of using work done formula and what is Fa=4F

Why i cannot just do like this: 

Work = Power x Time = 5W x 10s = 50 Joules

Force = 50 Joules / 2 meters = 25 Newtons

and can tutor explain other questions like what is the equation means

can tutor continue the next two questions also