the 3.10³ +5.10² +0.10+ 0.1 = 3500 28. Place the digits 7, 6, 8, 3, and 2 in the boxes to obtain = a. the greatest product. X b. the least product.
the 3.10³ +5.10² +0.10+ 0.1 = 3500 28. Place the digits 7, 6, 8, 3, and 2 in the boxes to obtain = a. the greatest product. X b. the least product.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 69E
Related questions
Question
#28
![ure to
ute the
1)
addition and part (b)
26. Discuss possible error patterns in each of the following
multiplications.
a. 34
X8
2432
27. Give reasons for each of the following steps.
35-100=(3-10 + 5)100
= (3.10+5)10²
= (3.10)10² +5.10²
= 3(10.10²)+5.10²
= 3·10³ +5.10²
= 3.10³ +5.10² +0.10+ 0.1
= 3500
28. Place the digits 7, 6, 8, 3, and 2 in the boxes to obtain
a. the greatest product.
b. 34
×6
114
x [
b. the least product.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d07973f-0a38-4398-b36b-77a6f08c0439%2F9ccab63f-b4f6-47db-bd37-98d6e2bac64f%2Fjsukoek_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ure to
ute the
1)
addition and part (b)
26. Discuss possible error patterns in each of the following
multiplications.
a. 34
X8
2432
27. Give reasons for each of the following steps.
35-100=(3-10 + 5)100
= (3.10+5)10²
= (3.10)10² +5.10²
= 3(10.10²)+5.10²
= 3·10³ +5.10²
= 3.10³ +5.10² +0.10+ 0.1
= 3500
28. Place the digits 7, 6, 8, 3, and 2 in the boxes to obtain
a. the greatest product.
b. 34
×6
114
x [
b. the least product.
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