that value K, in a way RK-4 when solving the issue y' = Y-x Y+x , Y (0) = 1 where h=0.25 15:- a) 0.2 b) 0.25 C) 0.5 d) 0-1

help me solve this

0. A particle moves along the x-axis. The velocity of the particle at time t is given by v(t) = 4 If the %3D t+1 position of the particle is x 1 when t = 2, what is the position of the particle when t = 4 ? (A) 0.617 (B) 0.647 (C) 1.353 (D) 5.713

Below are attempts at u-substitution by students. Explain where each student went wrong, then explain how to solve the problem. (a) Jane is evaluating x(2x + 5)² dx. She identifies u = 2x + 5, so du = and so dx = du. Thus,x(2x + 5)² dx Ja = 1/2/ 1/ ST. 2 with respect to u, she treats x as a constant, and xu² du. Since the integral is 1 1 -X 2 x.u² du - 1 -U³ 2dx, 3 = x(2x- c(2x + 5)³.

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