Testing a asking question. 1) mass of benzil = moles x molar mass of benzil= 0.35 mmol x 210.232 g/mol= 73.5812 x 10^-3 g= 73.58 mgmass of benzoin=0.35 mmol x 212.24 g/mol= 74.284 x 10^-3 g= 74.284 mg2)a) one mole of sodium borohydride (NABH4) can reduce four moles of aldehyde orketonethereforeone mole of sodium borohydride (NaBH4) can reduce 2 moles of benzil because benzilhas 2 ketone groupandfor 0.35 mmol of benzil , moles of NABH4 required = 0.35 mmol / 2 = 0.175 mmolthusmass of NaBH4 = 0.175 mmol x 37.83 g/mol= 6.62 mgb) as we know that for 0.35 mmol of benzil , only 6.62 mg of NaBH4 is requiredtherefore15 mg is very large and Only 0.35 mmol of benzil , leads to the result thatbenzil is the limiting reagent.3) the balanced reaction or the reaction of the NaBH4 with H2O is given asNABH4 + 3 H20NaH2BO3 + 4 H2 AABC is triangle with D and E the midpoints ofAB and AC respectively.EProve that BC=2DE.ВC

According to the mole concept, in terms of mass, the amount of substance in moles is equal to the…

Answered: Testing a asking question.

Science

Chemistry

Testing a asking question.

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter10: Energy

Section: Chapter Questions

Problem 9ALQ: hat is meant by the term driving forces? Why are mailer spread and energy spread considered to be...

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