Test the series for convergence or divergence. (-1)" (3n – 5) 2n + 5 n = 1 Evaluate the following limit. (If the quantity diverges, enter DIVERGES.) lim (-1) (3n - 5) 2n + 5 n- 00 Since lim (-1)" (3n – 5) |---Select-- ---Select--- n- 00 2n + 5 -Select--- the series is convergent the series is divergent Need Help? Watch It Master It

7" (f) Ž F(-8)*| n-1 n=1 Converges or Diverges: Sum(If Converges): [1-(-1)" | (g) n+1 Converges or Diverges: limit (If Converges): (h) ¿l-(-1)" n+1 n=1 Converges or Diverges: Sum(If Converges): 5 (i) -2, 2' 25 125 8 32 Converges or Diverges: limit (If Converges): 5 (j) -2+ 25 125 8 32 Converges or Diverges: Sum(If Converges):

Consider the series an where n=1 (-5n - 3)" (-3n-5)" In this problem you must attempt to use the Root Test to decide whether the series converges. Compute an = Which of the following statements is true? A. The Root Test says that the series converges absolutely. B. The Root Test says that the series diverges. L = lim √√|an| 11-00 Enter the numerical value of the limit L if it converges, INF if it diverges to infinity, MINF if it diverges to negative infinity, or DIV if it diverges but not to infinity or negative infinity. L= ✓ C. The Root Test says that the series converges conditionally. D. The Root Test is inconclusive, but the series converges absolutely by another test or tests. E. The Root Test is inconclusive, but the series diverges by another test or tests. F. The Root Test is inconclusive, but the series converges conditionally by another test or tests. Enter the letter for your choice here: