Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.01 significance level. The alternative hypothesis would be:   μ<0.8μ<0.8 p>0.8p>0.8 μ>0.8μ>0.8 μ≠0.8μ≠0.8 p<0.8p<0.8 p≠0.8p≠0.8 The test is:   right-tailed two-tailed left-tailed Based on a sample of 400 people, 71% owned cats The test statistic is:  (to 2 decimals) The p-value is:  (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis The conclusion is: At the 0.01 alpha level, I was unable to show that the proportion of people who own cats is significantly greater than 80 percent. At the 0.01 alpha level, I was unable to show that the proportion of people who own cats is significantly different than 80 percent. At the 0.01 alpha level, I was able to show that the proportion of people who own cats is significantly greater than 80 percent. At the 0.01 alpha level, I was able to show that the proportion of people who own cats is significantly less than 80 percent. At the 0.01 alpha level, I was unable to show that proportion of people who own cats is significantly less than 80 percent. At the 0.01 alpha level, I was able to show that the proportion of people who own cats is equal to 80 percent.

Test the claim that the mean GPA of night students is significantly different than 2.7 at the 0.04 significance level.The null and alternative hypotheses would be: H0:μ=2.7H0:μ=2.7H1:μ≠2.7H1:μ≠2.7 H0:p=0.675H0:p=0.675H1:p>0.675H1:p>0.675 H0:p=0.675H0:p=0.675H1:p<0.675H1:p<0.675 H0:μ=2.7H0:μ=2.7H1:μ>2.7H1:μ>2.7 H0:p=0.675H0:p=0.675H1:p≠0.675H1:p≠0.675 H0:μ=2.7H0:μ=2.7H1:μ<2.7H1:μ<2.7 The test is: left-tailed two-tailed right-tailed Based on a sample of 30 people, the sample mean GPA was 2.66 with a standard deviation of 0.16The p-value is:  (to 3 decimals)The positive significance level is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be:   H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 The test is:   right-tailed left-tailed two-tailed Based on a sample of 200 people, 87% owned catsThe p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

Test the claim that the mean GPA of night students is significantly different than 2.4 at the 0.2 significance level.The null and alternative hypotheses would be: H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:μ=2.4H0:μ=2.4H1:μ≠2.4H1:μ≠2.4 H0:μ=2.4H0:μ=2.4H1:μ>2.4H1:μ>2.4 H0:p=0.6H0:p=0.6H1:p<0.6H1:p<0.6 H0:μ=2.4H0:μ=2.4H1:μ<2.4H1:μ<2.4 H0:p=0.6H0:p=0.6H1:p>0.6H1:p>0.6 The test is: right-tailed left-tailed two-tailed Based on a sample of 31 people, the sample mean GPA was 2.36 with a standard deviation of 0.16The p-value is:  (to 3 decimals)The positive significance level is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis

In 1990, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephone company wants to perform a significance test to determine whether the average duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. The hypotheses are:                                H0: μ = 9.4 minutes                                HA: μ ≠ 9.4 minutesSuppose that the results of the sample lead to non-rejection of the null hypothesis. Classify that conclusion as a Type I error, a Type II error, or a correct decision, if in fact the mean duration of long-distance phone calls has changed from the 1990 mean of 9.4 minutes. Choose the best asnwer below:    A. Neither B. Type I error C. Type II error D.No error

Test the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 The test is: right-tailed two-tailed left-tailed Based on a sample of 65 people, 87% owned catsThe test statistic is:  (to 2 decimals)The critical value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis I dont understand this.

A researcher wants to test whether the mean height for men and women are different, using a significance level of 0.05. Which is the correct hypothesis? A Ho: P1 = P2 Ha: P1 P2 D Ho: P1 = μ2 Ha: H1 H2 O C A OF OE O B B Ho: P1 = P2 Ha: P1 P2 E Ho: P1 = μ2 Ha: 12 C Ho: P1 = P2 Ha: 1: P₁ P2 F H₂:₁ = 1₂ Ha: ₁ 2

Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The null and alternative hypothesis would be: Ho: p= 0.8 Ho: ≤ 0.8 Hop: 0.8 Ho:p> 0.8 Ho: 0.8 Ho:p 0.8 H₁:µ 0.8 H₁:p 0.8 The test is: right-tailed two-tailed left-tailed = Based on a sample of 300 people, 82% owned cats The p-value is: (to 2 decimals)

Test the claim that the proportion of men who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:μ=0.8H0:μ=0.8H1:μ<0.8H1:μ<0.8 H0:μ=0.8H0:μ=0.8H1:μ>0.8H1:μ>0.8 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 The test is: two-tailed right-tailed left-tailed Based on a sample of 100 people, 87% owned catsThe test statistic is:  (to 2 decimals)The positive critical value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis

Test the claim that the proportion of men who own cats is significantly different than 30% at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p = 0.3 Ho:p = 0.3 Ho:u = 0.3 Ho:µ = 0.3 Ho:p = 0.3 Ho:u = 0.3 H1:p # 0.3 H1:p > 0.3 H1:4 > 0.3 H1:µ < 0.3 H1:p < 0.3 H1:u + 0.3 The test is: left-tailed two-tailed right-tailed Based on a sample of 50 people, 22% owned cats The test statistic is: (to 2 decimals) The positive critical value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis Reject the null hypothesis