Test the claim that the mean GPA of night students is larger than 2 at the 0.025 significance level. The null and alternative hypothesis would be: Но: р < 2 Но:р %3D 0.5 Но:д — 2 Но:р < 0.5 Но:р > 0.5 Но:р> 2 Н:и > 2 Hi:p + 0.5 Hi:р # 2 H:р> 0.5 Н,:p < 0.5 H:р <2 The test is: left-tailed right-tailed two-tailed Based on a sample of 40 people, the sample mean GPA was 2.01 with a standard deviation of 0.06 The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level. The null and alternative hypothesis would be: Но : им — ИF Ho: Им — Иr Но: им — Ar Ho: Pм — Pr Ho:Pм — Pr Ho:рм — Pғ µf Ho:PM PF Ho:PM = PF Ho:PM H1: µM > µF H1:µM + HF H1:µM PF The test is: left-tailed right-tailed two-tailed Based on a sample of 20 men, 25% owned cats Based on a sample of 80 women, 35% owned cats The test statistic is: (to 2 decimals) (Hint: difference in proportions, not z) The positive critical value is: (to 2 decimals) (Hint: the proportion, not z) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis

Suppose data is obtained from 20 pairs of (x, y) and the sample correlation coefficient is 0.80. (a) Test the hypothesis that Ho: p = 0 against H₁ :p #0 with a = 0.01. Reject the null hypothesis. (b) Test the hypothesis that Ho: p = 0.25 against H₁: p = 0.25 with a = 0.01. Reject the null hypothesis. (c) Construct a 99% two-sided confidence interval for the correlation coefficient. Round your answer to 3 decimal places. < p < i i

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Test the claim that the mean GPA of night students is larger than 2.4 at the 0.025 significance level. The null and alternative hypothesis would be: Ho: µ = — 2.4 Но:р 2.4 Н: + 2.4 H:p> 0.6 H:д> 2.4 Hi:p #0.6 Hi:p < 0.6 Н:р < 2.4 The test is: left-tailed two-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 2.41 with a standard deviation of 0.03 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

The records of a casualty insurance company show that, in the past, its clients have had a mean of 1.7 auto accidents per day with a variance of 0.0025. The actuaries of the company claim that the variance of the number of accidents per day is no longer equal to 0.0025. Suppose that we want to carry out a hypothesis test to see if there is support for the actuaries' claim. State the null hypothesis H and the alternative hypothesis H, that we would use for this test. H0:__H 1:__

A researcher investigates whether cold medication effects mental alertness. It is known that scores on a standardized test containing a variety of problem-solving tasks are normally distributed with  = 64 and  = 8. A random sample of n = 16 teenage and a sample of n = 25 adults are given the drug and then tested. On average, the teenagers scored and average of ? = 58 and the adults scored and average of M = 65.5.a. Are the data sufficient to conclude that the medication significantly reduces mental alertness in teenagers? Test with  = .01.b. Are the data sufficient to conclude that the medication significantly increases mental alertness in adults? Test with  = .01.

Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significance level. The null and alternative hypothesis would be: Но: дм — Мр Но: рм — МF Но: рм — Pr Но: рм — рF Но: им — МЕ Но: рм — РF PF Ho:HM = µf Ho:PM = Pf H1: µM + HF H1:µM PF H1:µM > µF H1:PM < PF The test is: left-tailed right-tailed two-tailed Based on a sample of 60 men, 35% owned cats Based on a sample of 40 women, 55% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis

The records of a casualty insurance company show that, in the past, its clients have had a mean of  1.8  auto accidents per day with a variance of  0.0036 . The actuaries of the company claim that the variance of the number of accidents per day is no longer equal to  0.0036 . Suppose that we want to carry out a hypothesis test to see if there is support for the actuaries' claim. State the null hypothesis  H0  and the alternative hypothesis  H1  that we would use for this test. H0:H1:

Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.02 significance level. The null and alternative hypothesis would be: Но: HF Ho: UM = µF Ho:PM — pF Ho:рм PF Ho: им — MF Ho:; PF Нi: рм > иF Hi: рм # pF Hi:рм рF Hi: рм < pF Hi:рм # pғ The test is: right-tailed two-tailed left-tailed Based on a sample of 80 men, 25% owned cats Based on a sample of 40 women, 50% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis