(Feedback and Control System) Instructions: In order to solve. The (1st picture yellow) is the guide to solve the (2nd Picture) you need to follow the first picture enable to solve. Step 1: Current LoopsStep 2: Remove IntegralsStep 3: Simplify Capacitordvcic = C=InductorResistorVr = İRRdi,v = Ldt%3Ddt1/5FVE r ot the currenty* step1 Current loopsエster3 Simplfi-Façtur ot the currens%3Dエ Gu)_se ta Ci -ia)8%3DStep a: Remove integ ralsIy() =+ eiーia)e在 a)OUG)= 80i, +1oDUCt)= 80i,+ 104-loi2Du(4)=(YD+l0), -16indizP)p+('-?) /+ 10=ール,(O'+on)%3D

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Answered: TE 1/5F

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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(Feedback and Control System) Instructions: In order to solve. The (1st picture yellow) is the guide to solve the (2nd Picture) you need to follow the first picture enable to solve.

Step 1: Current Loops

Step 2: Remove Integrals

Step 3: Simplify

Capacitor
dvc
ic = C=
Inductor
Resistor
Vr = İRR
di,
v = L
dt
%3D
dt
1/5F
VE

r ot the currenty
* step1 Current loops
エ
ster3 Simplfi
-Façtur ot the currens
%3D
エ Gu)_se ta Ci -ia)
8
%3D
Step a: Remove integ rals
Iy() =+ eiーia)e
在 a)
OUG)= 80i, +1o
DUCt)= 80i,+ 104-loi2
Du(4)=(YD+l0), -16in
diz
P)
p+('-?) /
+ 10
=ール,(O'+on)
%3D

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