College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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The resistance of the loop in (Figure 1) is 0.16 Ω.
Is the magnetic field strength increasing or decreasing?
At what rate (T/s)?
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- A singly charged positive ion has a mass of 2.46 x 10-26 kg. After being accelerated through a potential difference of 242 V, the ion enters a magnetic field of 0.590 T, in a direction perpendicular to the field. Calculate the radius of the path of the ion in the field. cmarrow_forwardIn the figure (Figure 1) a conducting rod of length L = 40.0 cm moves in a magnetic field B of magnitude 0.410 T directed into the plane of the figure. The rod moves with speed v = 5.60 m/s in the direction shown. Part F What is the potential difference across the rod if it moves parallel to ab? Express your answer in volts. Figure < 1 of 1 ? V = 0.91 V B х ахarrow_forwardc. What is the resistance of the coil given that the diameter of the wire is 2.00 mm? (Recall, resistance of wire is given by R = ρL/A, where ρ is the resistivity of the metal, L is the length of the wire, and A is the cross-sectional area.)arrow_forward
- An electrically conductive rod is moving through a uniform magnetic flux at a constant velocity at right angles, as shown by its cross-section in the diagram. The velocity is in the x-direction, the rod is of length 150 mm along z, and the magnetic flux density is 0.2 T in the positive y-direction. Speed If the potential difference (voltage) across the ends of the rod is 5.8 Volts, what is the magnitude of the velocity? m/s Not perpendicular If the rod is passing through the flux with its axis not at right angles what can you be sure of? The speed to generate 5.8 V would have to be smaller. • The speed to generate 5.8 V would have to be bigger. The speed to generate 5.8 V would be the same.arrow_forwardThe figure below shows a loop of wire of mass ?=0.0200 kg, width ?=0.0554 m, and resistance ?=0.235 ? dropping out of a region of constant magnetic field of magnitude ?=2.51 T pointing into the page. As long as the top of the loop is in the magnetic field, the equation describing the speed of the loop ? is given by ???/??+??^2?^2/?=??. Replacing the speed by the current ?. this equation has the same form as that for a series RL circuit. What is the speed of the loop after ?=0.440 s?arrow_forwardA stationary square coil of area 0.1 m2 is brought over time of 2 s into the magnetic field 8.5 T with its plane perpendicular to the magnetic field. The coil has 1523 turns. Calculate the magnetic flux linkage through the coil. Give your answer in SI units.arrow_forward
- In the figure (Figure 1) the top wire is 1.1 −mm−mm -diameter copper wire and is suspended in air due to the two magnetic forces from the bottom two wires. The current flow through the two bottom wires is 75 AA in each. Calculate the required current flow in the suspended wire. Express your answer using two significant figures. ICu=____________Aarrow_forwardShown in the figure below is a rectangle of wire immersed in a magnetic field. The rectangle has length L = 2 meters, width w = 2 meters, and a resistance of R = 7.97 Ω. The magnetic field varies with time according to the equation:B(t) = 5t2 + 2t5As a result of the varying field, a voltage and current will be established in the loop.Answer all of the following: What is the FORMULA for the rate of change of magnetic field with time, dB dt = What is the FORMULA for the rate of change of magnetic flux with time, dΦB dt = What is the voltage in the circuit at t=1.1 seconds? Volts What is the current in the circuit at this same time? Amps NOTE: Make all formulas POSITIVE (field and flux). Make all values POSITIVE (voltage and current). Format your equations as atn + btm where a,b,n,m are numerical values. Example: 12t2 + 72t3arrow_forward
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