Taking into account that dG = Vdp –SdTA) write the Maxwell relation between changes in volume and entropyWhat is true about temperature? A) V = (ôp/ôS)T B) V = (ôG/ôp)v C) V = (ôG/ôT), D) V = (ôS/ôT),

The four maxwell equations are as shown below. Hence the maxwell relation between changes in volume…

Answered: Taking into account that dG = Vdp –SdT…

Chemistry

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

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Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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P3B.4 The molar heat capacity of N,(g) in the range 200 K to 400 K is given by Cm/(JK mol) = 28.58 + 3.77 x 10°(T/K). Given that the standard molar entropy of N,(g) at 298 K is 191.6 J Kmol, calculate the value at 373 K. Repeat the calculation but this time assuming that C, is independent of %3D D.m temperature and takes the value 29.13 J K mol. Comment on the difference between the results of the two calculations.
need sonn both parts
Part B Based on the value of A,U = -1370 kJ mol-1,determine the value of A,H for the combustion of ethanol at 298 K. C2H5OH(I) + 3 O2(g) →2 CO2(g) + 3 H,0() Enter your answer using four significant figures. Πνα ΑΣφ ? A,H = kJ mol 1
1. (a) In reaching equilibrium, how much heat transfer occurs from 1.2 kg of water at 40°C when it is placed in contact with 1.2 kg of 20°C water? Specific heat of water c=4186 J/(kg°C) Hint: If the masses of water are equal, what is the equilirium temperature of the water mixture? Q= ✓ J (b) What is the change in entropy due to this heat transfer? AS total ✔J/K (c) How much work is made unavailable, taking the lowest temperature to be 20°C? = W unavailable ✓ J
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Calculate the change in entropy that occurs in the system when 1.61 mol of diethyl ether (C4H10O) condenses from a gas to a liquid at its normal boiling point (34.6 °C). The heat of vaporization is 26.5 kJ/mol. Express your answer with the appropriate units. AS = μÅ Value Units ?
Recall that for a monoatornic ideal gas, CV = (3/2) *R . If an equal number of moles of any three ideal gases are mixed, what is the change in entropy?
(a) Suppose that attractions are the dominant interaction between gas molecules, and the equation of state is p = nRT/V – n2a/V2. Determine the work (W(non-ideal gas)) of reversible, isothermal expansion of such a gas from initial volume V (initial) = 20.0 L to final volume V(final) = 40.0 L if n = 2.00 mol, T = 300 K, and a = 3.621 atm-L2/mol2. Watch your units. (b)Determine the work (W(ideal gas) of reversible, isothermal expansion of an ideal gas from initial volume V (initial) = 20.0 L to final volume V(final) = 40.0 L if n = 2.00 mol and T = 300 K. (c) Show the difference W(non-ideal) – W(ideal). If all your calculations are done correctly, this result shows you the effect of attractive interaction between gas particles on the work done by the system.
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This question has multiple parts. Work all the parts to get the most points. The Gibbs Free Energy equation is given by the equation: AG = AH - TAS Where: AG = Gibbs Free Energy change AH = Enthalpy change T = temperature AS = Entropy change In order to solve for the temperature, T, in two steps you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-hand side of the expression: (Be sure that the answer field changes from light yellow to dark yellow before releasing your answer.) +AG = +AH - TAS Drag and drop your selection from the following list to complete the answer: 1 1 -ΔΗ ΔΗ AH AH

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Taking into account that dG = Vdp –SdT A) write the Maxwell relation between changes in volume and entropy What is true about temperature? A) V = (ôp/ôS)T B) V = (ôG/ôp)v C) V = (ôG/ôT), D) V = (ôS/ôT),