Table 2: Measured Voltage Gain versus Frequency with Vs(p-p) = 0.2 VFrequency (Hz) Voutp-p) (V)| Ay= Vout/Vs Ay (dB) = 20 log (4₂)501001502004008001k2k4k8k10k20k50k100k200k500k600k800kIM2M4M6M8M10M20M50M100M0.9871.8052.3022.5962.9783.1063.1253.1453.1483.1513.1513.1513.1513.1513.1513.1513.1513.1513.1513.1453.1313.1063.0753.0322.7441.8221.044

Given that, we have Vs(p-p)=0.2 V, various frequency & Vout(p-p) We have to find gain Av &…

Table 2: Measured Voltage Gain versus Frequency with Vs(p-p) = 0.2 V Frequency (Hz) Voutp-p) (V) Ay= Vou Vs Ay (dB) = 20 log (4₂) 50 100 150 200 400 800 1k 2k 4k 91. 0.987 1.805 2.302 2.596 2.978 3.106 3.125 3.145 3.148 2.151

Table 2: Measured Voltage Gain versus Frequency with Vs(p-p) = 0.2 V Frequency (Hz) Voutp-p) (V) Ay= Vou Vs Ay (dB) = 20 log (4₂) 50 100 150 200 400 800 1k 2k 4k 91. 0.987 1.805 2.302 2.596 2.978 3.106 3.125 3.145 3.148 2.151

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Table 2: Measured Voltage Gain versus Frequency with Vs(p-p) = 0.2 V
Frequency (Hz) Voutp-p) (V)| Ay= Vout/Vs Ay (dB) = 20 log (4₂)
50
100
150
200
400
800
1k
2k
4k
8k
10k
20k
50k
100k
200k
500k
600k
800k
IM
2M
4M
6M
8M
10M
20M
50M
100M
0.987
1.805
2.302
2.596
2.978
3.106
3.125
3.145
3.148
3.151
3.151
3.151
3.151
3.151
3.151
3.151
3.151
3.151
3.151
3.145
3.131
3.106
3.075
3.032
2.744
1.822
1.044

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