Table 1. Structure of Dye Sudan IV N,N- Dimethyl-p-phenylazoaniline N,N-Dimethylindoaniline 4-o-tolyazo-o-toluidine waveleng Color of Solid Observed Color of Dye Solution (A max) by your dye. Complementary Color of Dye Solution 10 Js and c (speed light) 0 998 x10 m

In the UV–vis spectrum of benzene, the absorption that corresponds to the HOMO–LUMO transition occurs at 184 nm.How does this compare to the corresponding electron transition in hexa-1,3,5-triene (see Table 15-1)? Explain why there is a significant difference.

If the absorption peak(s) was present in the IR spectrum, fill in the approximate wavenumber(s). If the absorption peak(s) was absent in the IR spectrum, write “absent”.

How do I interpret this mass spec graph in order to determine the identity from the list of unknowns below?

Analyze the 1H NMR data and talk about the coupling, splitting pattern, equivalents, and the j coupling, and the hydrogens

Analysis of 1 5-bis(4’-methoxyphenyl)-1 4-pentadien-3-one by NMR. Please label the chemical shift (ppm), integration, splitting (single, doublet, triplet), and fragments (C-C). Is the C double bond C cis or trans?

1. Given the following 'H NMR spectra. A. Draw structure of compound. В. Label peaks (Ha, He, Hs, etc.) and indicate multiplicity. Acetamide 11 10 9 8. 7 4 3 1 ppm Fumaric acid 22 20 18 16 14 12 10 8 4 HP-00-250 ppm

11 An unknown compound A has the molecular formula C12H16O. Compound A absorbs strongly in the IR at 1700 cm-1. The NMR spectral data for compound A are given below. What is the structure of compound A? A. absorption singlet triplet "ost of B. quartet broad singlet ppm 1.0 1.2 2.2 7.0 C. D. ratio of absorbing H's 6 325 2 the

Calculate the degree of unsaturation. Assign the relevant peaks in the IR spectrum. Assign the peaks in the 13C NMR spectrum. Assign the peaks in the 1H NMR spectrum.

3. (Chapter 13 - Q58c) The compound whose H NMR spectrum is shown has the molecular formula C3H9B1. Follow the following questions to predict the unknown structure. Chem. Rel. shift area 3.16 1.00 3.56 1.00 1.00 1.50 Z18 729 TMS 10 O ppm Chemical shift (8) ng 3(a) Degree of the unsaturation of this compound = 3(b) The two peaks at 3.16 8 and 3.56 ő indicate two triplets Yes or NO = 3(c) The compound has 2 CH2 groups Yes or No = 3(d) Depending on the two triplets' chemical shifts one of the CH2 may have attached to the Br, Yes or No = 3(e) The multiplet at 7.18 õ to 7.29 õ indicate that compound is. disubstituted benzene - 3(f) The name of the unknown compound is = Intensity