T1 12v 6v A 4.5v 3v To Diode circuit Ov common B D1 A C1 1000pF RL 1B4B42 3k0 ind the output voltage across the load RL VL output current through RL nd the power dissipated by RL for the following input voltages w4.5v,6v,9v & 12
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- What is CEMF?Q4) Determine and sketch the output voltage across the load resistor (RL) for the circuit shown below. (assume Si diodes) V_DC 0.75 0.25 V_SIN Y SIN as RL -1 v SOR V_SQR 0.75 -0.75 V_TRI V TRI asA clamper circuit has 20 Vp-p. 100Hz square wave input voltage. The circuit consists of silicon diode IN4001 and 3V battery as shown in Figure 1 C. 0.1 µF D R Vi(t) 50 k2 Vo(t) 3 V Figure 1 a) Find the output voltage for all input voltages values. b) Sketch the output waveform, Vo(t).
- The cut-in voltage for each diode in the circuits shown in Figure Pl.30 is V, = 0.6 V. For each circuit, determine the diode current I, and the voltage Vo (mea- sured with respect to ground potential). Q7 R= 10 k2 Vo oVo Ip R= 10 k2 5 V 5V 5 V 5 V (a) (b) R= 10 k2 Vo 5V E 5 V (c)For the circuit in the figure, let V input = 8V, Ri = 12ohms, RL = 10ohms, and VZ = 3.3V. Determine the voltages and currents of the resistors and the current of the zener diode.Vps = 10 V R = 0.1k02 ww -ovo R₁. Consider the Zener diode circuit shown in figure. The Zener diode voltage is Vz= 5.8V at Iz= 10mA and the Zener resistance is rz = 200. a) Find the output voltage for RL = 1k0 b) Find the change in the output voltage when the load resistance varies +ARL.
- Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20VV, is a 60Hz source with a peak voltage VP-120V is feeding a rectifier, assume ideal diode. The load resistance has a value of R= 10 k0. If ripple voltage Vr = 2V, the Diode average current Ipavg is VI Select one: a. + e. None Ob. 580mA Oc. 850mA Od 245mA 425mA D C: www tu Vo Q6Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to IL-DC =0:5A RL VL-DC =20V 220V omsb O 001 F O 0.02 F O 0.0167F O None of the above Activate
- In the clamping circuit below, assume the diode has Von-0.7V and V₁ is a sinusoidal wave with a peak-to-peak amplitude of 10V. How much is the maximum value of the output voltage signal (Vmax)? And how much will it be if we set V₂=2V? Input V1 C1 0.1e-6 9.3 V and 7.3 V 9.3 V and 11.3 V 11.3 V and 7.3 V O 7.3 V and 12.0 V O 12.0 V and 7.3 V Output D1 1N4148 .tran 30-3 V2 0 Vmax V(output) 0.0ms putput MAN Input 0.6ms 1.2ms V(input) 1.8ms 2.4ms 3.0msAfter replacing R5 with diode IN4007 (switch K3 to diode side) .What conclusion can you draw from analysis of this step ?Questions 1 V, is a 60Hz source with a peak voltage VP-120V is feeding a rectifier, assume ideal diode. The load resistance has a value of R= 10 kn. If ripple voltage Vr = 2V, the Diode average current Ipavg is VI Select one: None b. 580mA 850mA O c. Od 245mA O e. 425mA D C C: R www Q+ Vo