Systems of linear equations have unique solutions. Find the solution using Gaussian elimination or the solution elimination using Gauss-Jordan elimination! x+y+6z 3 x+y+3z 3 x+2y+4z 7

Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTION. If there are an infinite number of solutions, set x3 = t and solve for X₁ and X2.) X1 - 3x3 = -5 3x1 + x₂ - 2x3 = 1 2x1 + 2x2 + x3 = 1 (X1, X2, X3) = Need Help? Read It ►

Solve the system of linear equations. If there is no solution, write NO SOLUTION. If there are infinitely many solutions, express your answer in terms of the parameters t and/or S 2x1+6x2-4x3 = 4 X1+3x2+X3+6x 4 = – 1 3x1 + 9x2-X3+ 10x4 = 1