suspension or You are requested to design an aut shock absorber system. In order to simplify the problem to one dimensional multiple mass-spring-damper system, a quarter vehicle model is used. The system parameters and free-body diagram of such system is shown below. M₁: Automobile body mass M₂: Wheel and suspension mass K₁: Spring constant of suspension system K₂: Spring constant of wheel and tire B: Damping constant of shock absorber = 2500 kg = 320 kg = 80,000 N/m = 500,000 N/m = 350 N-s/m Automobile- Suspension system Wheel- M₁₂ M₂ Rn Ka x₁(1) x₂(1) Tire

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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You are requested to design an automotive suspension or
shock absorber system. In order to simplify the problem to one
dimensional multiple mass-spring-damper system, a quarter vehicle
model is used. The system parameters and free-body diagram of such
system is shown below.
M₁: Automobile body mass
M₂: Wheel and suspension mass
K₁: Spring constant of suspension system
K2: Spring constant of wheel and tire
B: Damping constant of shock absorber
(a) Obtain the transfer function of
X₁ (s)
F(s)
T₁(s) =
= 2500 kg
= 320 kg
and T₂(s) =
= 80,000 N/m
= 500,000 N/m
= 350 N-s/m
Automobile-
Suspension
system
Wheel-
M₁
M₂
X₁ (s) - X₂ (S)
F(s)
in terms of the parameters of mass, damper and elastance (M, B and K).
(b) Express the T₁ (s) and T₂ (s) with numerical values.
c) Plot the x₁ (t) and x₁ (t) = x₂(t) outputs of this passive suspension system for the input torque
f(t) = 2,000 N.
fit) K₂
x₂(t)
-Tire
Transcribed Image Text:You are requested to design an automotive suspension or shock absorber system. In order to simplify the problem to one dimensional multiple mass-spring-damper system, a quarter vehicle model is used. The system parameters and free-body diagram of such system is shown below. M₁: Automobile body mass M₂: Wheel and suspension mass K₁: Spring constant of suspension system K2: Spring constant of wheel and tire B: Damping constant of shock absorber (a) Obtain the transfer function of X₁ (s) F(s) T₁(s) = = 2500 kg = 320 kg and T₂(s) = = 80,000 N/m = 500,000 N/m = 350 N-s/m Automobile- Suspension system Wheel- M₁ M₂ X₁ (s) - X₂ (S) F(s) in terms of the parameters of mass, damper and elastance (M, B and K). (b) Express the T₁ (s) and T₂ (s) with numerical values. c) Plot the x₁ (t) and x₁ (t) = x₂(t) outputs of this passive suspension system for the input torque f(t) = 2,000 N. fit) K₂ x₂(t) -Tire
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