Suppose you are standing on a field, which is at a latitude of 40 5/6', and that you are 2.0 m tall. (a) Analytically find the speed of your feet, v, due to the rotation of the Earth. (Assume that the Earth is a perfect sphere, which is not, of radius R = 6378 km and that a day is exactly 24 hours long.) (b) Using your result from (a), determine the centripetal acceleration of your feet. 1 (c) Repeat parts (a) and (b) for your head and compute the difference between the acceleration at your head and feet. Show how round-off can corrupt your calculation and offer a way to fix the problem.

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2. Suppose you are standing on a field, which is at a latitude of 40 5/6°, and that you are 2.0 m tall.
(a) Analytically find the speed of your feet, v, due to the rotation of the Earth. (Assume that the
Earth is a perfect sphere, which is not, of radius R = 6378 km and that a day is exactly 24 hours
long.)
(b) Using your result from (a), determine the centripetal acceleration of your feet.
1
(c) Repeat parts (a) and (b) for your head and compute the difference between the acceleration
at your head and feet. Show how round-off can corrupt your calculation and offer a way to fix
the problem.
Transcribed Image Text:2. Suppose you are standing on a field, which is at a latitude of 40 5/6°, and that you are 2.0 m tall. (a) Analytically find the speed of your feet, v, due to the rotation of the Earth. (Assume that the Earth is a perfect sphere, which is not, of radius R = 6378 km and that a day is exactly 24 hours long.) (b) Using your result from (a), determine the centripetal acceleration of your feet. 1 (c) Repeat parts (a) and (b) for your head and compute the difference between the acceleration at your head and feet. Show how round-off can corrupt your calculation and offer a way to fix the problem.
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Step 1 Introduction

Latitude gives your vertical angular position from the center, where the equator is 0°. This angle also changed the forces you feel on Earth due to its rotation as well as gravity. 

Centripetal acceleration is the acceleration that is pointed inwards in a circular motion. It is the force that keeps an object in circular motion as opposed to just flying off. 

 

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