Suppose you are an engineer for a motorcycle manufacturer. You are assigned to the team designing the motorcycle's rear suspension. You are studying the properties of springs that are strained horizontally. Your experimental setup is animated in the simulation (linked below). In this simulation, a particle is given an initial velocity at x = 0, and it moves in the + x direction while slowing down due to the elastic force. When the block is at x = 0, the spring is unstrained, and therefore exerts no force on the block. So x = 0 is the particle's equilibrium location. The end of the interval is taken to be at the one-meter mark, which is where the particle is momentarily at rest. That is, x₂ = 1 m. Run the animation now. Simulation The Elastic Force Acts on a Moving Block The simulation shows the true spring force on the block as it moves (see the solid blue arrow labeled "Exact Force"), and it also shows an approximation to the exact force (see the dashed blue arrow labeled "Approximate Force"). Note the behavior of the approximate force. It jumps discontinuously to a new value each time the block completes a displacement of size Ax = x₂/N. Both the true and the approximate forces are plotted in the simulation above the animated motion. The area between the plot of the approximate force and the x-axis is a series of narrow rectangles shaded in light blue in the simulation. The exact force is the line Fx = kx, which is shown in green in the plot.

Hey I am stuck on this question my potential function is f(x,y,z) = c/(Sqrt(x^2 + y^2 + z^2) and I got W = c/d2 - c/d1 but that is wrong.

What is the dot product A•B if A = 2x - 3y and B = 15x + 10y?

A spring with k = 15 N/m with equilibrium length 30 cm is attached vertically to a surface and then allowed to come to equilibrium, after which a weight with mass 0.2 kg is attached to the top side of the spring. → How much work does the Earth do on the weight via gravity between its initial position and the new equilibrium height? Explicitly compute the work with an integral.

A child of mass m = 16 kg slides down a slide of height h = 2.7 m without friction. Let gravitational potential energy be zero at ground level. a)Write an expression for the child's total mechanical energy, E, at the top of the slide, in terms of the variables in the problem and the acceleration due to gravity g.  b)Calculate the change in the child's potential energy, ΔU in joules, from the top to the bottom of the slide at ground level (i.e. ΔU = Uground - Utop).  c)What is the child's final speed, vf in m/s?

A person is 170 cm tall. He holds a 10 kg object on his head for 10 minutes. How much work is done on the object?

How did you solve D? Wouldn't it's distance be different from that of Point 1 to Point 2 as would be Point 3 to Point 2 and shouldn't that effect the answer for work needed to be done?

Needs Complete typed solution with 100 % accuracy.

Given a vector field F=2xi+3xyj that represents the force of the wind on a sailboat, what is the work done by the wind on a boat traveling along a path defined by y=x^2 from a position (1,1) to a position (5,25)? Assume positions are given in kilometers and that force is in newtons. Note: To make units easy, a newton times a meter is a joule. A newton times a kilometer is a kilojoule (kJ). But F returns newtons.

What external work is necessary to bring at constant speed, from infinity, four point loads of 2nC to the four corners of a square with an edge measuring 0.14m? Answer: 1.39uJ Please show steps, explanation and formulas for my own understanding. Thankyou