Suppose we want to test the hypothesis that the probablity that a semicanductor is defective is less than O 05. To this end, we take a sample of 200 devices and find that 6 are defective. Al level of significance 0.05, what can we conclude? Oa The z statistic -13. and the p-value 0.096. Therefore, we fail to reject the nul hypothesis. O. The z statistic -2 3. and the p-value 0.03. Therefore, we reject the null hypothesis Oc Background conditions are not satisfied, therefore we cannot conduct this hypothesis test O .The z statistic -1.3. and the p-value 0.046. Tharafore, we raject the null hypothesis.

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Suppose we want to test the hypothesis that the probability that a semiconductor is defective is less than 0 05. To this end, we take a sample of 200 devices and find that 6 are defective. AI level of significance 0.05, what can we conclude?
O a. The z statistic -1.3. and the p-value 0.096. Therefore, we fail to reject the null hypothesis.
O b. The z statistic -2.3. and the p-value 0.03. Therefore, we reject the null hypothesis
Oc Background conditions are not satisfied, therefore we cannot conduct this hypothesis test
O d. The z statistic -1.3, and the p-value 0.046. Therefore, we reject the null hypothesis.
Transcribed Image Text:Suppose we want to test the hypothesis that the probability that a semiconductor is defective is less than 0 05. To this end, we take a sample of 200 devices and find that 6 are defective. AI level of significance 0.05, what can we conclude? O a. The z statistic -1.3. and the p-value 0.096. Therefore, we fail to reject the null hypothesis. O b. The z statistic -2.3. and the p-value 0.03. Therefore, we reject the null hypothesis Oc Background conditions are not satisfied, therefore we cannot conduct this hypothesis test O d. The z statistic -1.3, and the p-value 0.046. Therefore, we reject the null hypothesis.
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