Suppose we store an array of two 32-bit numbers {0x12345678, 0x9ABCDEF0} starting at memory address 0x100. If we stored this big-endian, which byte of our data would be stored at memory address 0x104? A. 9A B. 12 C. FO O D. 78 O E. None of the above (or N/A)

You are to write an Intel x86 assembly language program which makes useof a loop to access the individual elements of the array containing the ASCIIcharacters. You are to initialize the array with the following db directive: message db 'juMping JAck flaSh #1',10, 0 The ASCII character represented by decimal value 10 (0x0A) is the line feedcharacter (similar to endl in C++). The byte with all zeros (the so called NULL character in ASCII) is used to represent the end of the string.   Before entering the loop, which performs the case conversion, the program is to display on the screen the (original) contents of the string. Within the loop, the program is to determine whether the current character represents a lower case character. If the character is lower case, it is to be converted into its uppercase version. Non-alphabetic characters are to remain as is. Upon convertingall the lower case characters, the program is to display the string on the screen. Here is an example of a correct…