Suppose the position of an object moving in a straight line is given by s(t)=t² +6t+5. Find the instantaneous velocity when t = 6. The instantaneous velocity at t = 6 is

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10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Problem Statement:**

Suppose the position of an object moving in a straight line is given by \( s(t) = t^2 + 6t + 5 \). Find the instantaneous velocity when \( t = 6 \).

**Solution:**

To find the instantaneous velocity, we need to take the derivative of the position function, \( s(t) \), with respect to time \( t \), giving us the velocity function \( v(t) \).

The position function is:
\[ s(t) = t^2 + 6t + 5 \]

The derivative, or velocity function, is:
\[ v(t) = \frac{d}{dt}(t^2 + 6t + 5) = 2t + 6 \]

Substituting \( t = 6 \) into the velocity function:
\[ v(6) = 2(6) + 6 = 12 + 6 = 18 \]

Therefore, the instantaneous velocity at \( t = 6 \) is \( 18 \) units per time interval.
Transcribed Image Text:**Problem Statement:** Suppose the position of an object moving in a straight line is given by \( s(t) = t^2 + 6t + 5 \). Find the instantaneous velocity when \( t = 6 \). **Solution:** To find the instantaneous velocity, we need to take the derivative of the position function, \( s(t) \), with respect to time \( t \), giving us the velocity function \( v(t) \). The position function is: \[ s(t) = t^2 + 6t + 5 \] The derivative, or velocity function, is: \[ v(t) = \frac{d}{dt}(t^2 + 6t + 5) = 2t + 6 \] Substituting \( t = 6 \) into the velocity function: \[ v(6) = 2(6) + 6 = 12 + 6 = 18 \] Therefore, the instantaneous velocity at \( t = 6 \) is \( 18 \) units per time interval.
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