Suppose the mean height in inches of all 9th grade students at one high school is estimated. The population standard deviation is 5 inches. The heights of 8 randomly selected students are 63, 60, 74, 68, 60, 66, 72 and 61. x¯ = Margin of error at 99% confidence level = 99% confidence interval =

Q.3/ Assume that the following five numbers are sampled from a normal distribution: 2, 3, 5, 6 and 9 and the standard deviation is not known. Compute the 95% confidence interval.

In a study of 110 women and 116 men, it was found that mean body temperature for women was 97.690 F  and mean body temperature for men was 97.450 F.   Assume that the populations are independent, and the standard deviations were found to to be 0.89o F for women, and 0.660 F for men.  Use an α = 0.05 significance level to test the claim that woman and men have different mean body temperatures.     For full credit your hypothesis test must include:  the claim, the null and alternate hypothesis, your test statistic and corresponding p-value, your decision, and the interpretation of your decision as it relates to the claim.  It is acceptable to use technology to calculate the test statistic and the p-value here.

You measure 35 backpacks' weights, and find they have a mean weight of 64 ounces. Assume the population standard deviation is 4 ounces. Based on this, construct a 99% confidence interval for the true population mean backpack weight. Give your answers as decimals, to two places + ounces

Suppose the mean height in inches of all 9th grade students at one high school is estimated. The population standard deviation is 3 inches. The heights of 10 randomly selected students are 68, 62, 68, 75, 71, 60, 69, 62, 69 and 70. x¯ = Margin of error at 95% confidence level = 95% confidence interval = [

Ten randomly selected automobiles were stopped and the tread depth of the right front tire was measured. The mean was .32 inch, and the standard deviation was .08 inch. Assume the variable is normally distributed. Find the 98% confidence interval of the mean for the population. Find the 90% confidence interval of the mean for the population. Please show all work

An auditor takes a random sample of 880880 invoices from the 9510 invoices relating to the activities of a company in 2019. The sample mean value of the sampled invoices was £126 and the sample standard deviation was £58. Find a 99% confidence interval for the mean value of all the invoices for 2019. Round to 3 decimal places The records of the company states that the total income from the 9510 invoices was £1150710. The auditor's sample evidence does not support this stated total. True or false?  What is the probability, rounded to 3 decimal places, that the company's income does not exceed the value in the records?

You measure 40 turtles' weights, and find they have a mean weight of 63 ounces. Assume the population standard deviation is 7.5 ounces. Based on this, construct a 90% confidence interval for the true population mean turtle weight. Give your answers as decimals, to two places ounces

When 77 campers are randomly selected and surveyed, it was found that the average number that prefer to camp at the beach was 16. Assume the population standard deviation is 2.3. Construct a 90% confidence interval for the true population mean of the number of campers who prefer to camp at the beach. Give your answers to 3 decimal places. Error =

You measure 40 turtles' weights, and find they have a mean weight of 66 ounces. Assume the population standard deviation is 13.5 ounces. Based on this, construct a 99% confidence interval for the true population mean turtle weight. Give your answers as decimals, to two places + ounces