Suppose that x is a primitive root modulo n, where n > 1 is an odd integer. If (n) = 23548, determine the total number of primitive roots modulo n.

Algebra: Structure And Method, Book 1
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ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.7: Problem Solving: Consecutive Integers
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Intro to Elementary Number Theory Homework Problems.

 

Suppose that is a primitive root modulo n, where n > 1 is an odd integer. If (n) = 23548, determine the total number of primitive roots modulo n.
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Transcribed Image Text:Suppose that is a primitive root modulo n, where n > 1 is an odd integer. If (n) = 23548, determine the total number of primitive roots modulo n. Type your answer...
Find all of the primitive roots of p = 89 (recall that we defined primitive roots to be certain integers strictly between 0 and n). Enter the sum of all primitive roots, i.e., if
91,92,..., 9m
are all of the primitive roots of n, enter
below.
Hints:
91 +92 +
+9m
• 2 is not a primitive root of any prime p≥ 3 such that p = 1,7 (mod 8).
• 3 is not a primitive root of any prime p > 5 such that p = (-1)-1)/2 (mod 3).
• 5 is not a primitive root of any prime p≥ 7 such that p = 1 (mod 5).
• 7 is not a primitive root of any prime p > 11 such that p = (-1)(-1)/2 (mod 7).
Type your answer...
Transcribed Image Text:Find all of the primitive roots of p = 89 (recall that we defined primitive roots to be certain integers strictly between 0 and n). Enter the sum of all primitive roots, i.e., if 91,92,..., 9m are all of the primitive roots of n, enter below. Hints: 91 +92 + +9m • 2 is not a primitive root of any prime p≥ 3 such that p = 1,7 (mod 8). • 3 is not a primitive root of any prime p > 5 such that p = (-1)-1)/2 (mod 3). • 5 is not a primitive root of any prime p≥ 7 such that p = 1 (mod 5). • 7 is not a primitive root of any prime p > 11 such that p = (-1)(-1)/2 (mod 7). Type your answer...
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