
A First Course in Probability (10th Edition)
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Author: Sheldon Ross
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Transcribed Image Text:Suppose that X and Y are random variables with E(X) = 2 , E(Y) = 5 and E(X²) = 8,
E(Y?) = 30 and cov(X – 2Y,3X – 4Y) = -12, then cov(2X – 3, –5Y + 4) is equal to:
Hint: cov(aX + bY,cx + dY) = acV(X) + bdV(Y) + (bc + ad)cov(X,Y)
-59
-120
-64
-30
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