Suppose that we are interested in hypothesis testing and confidence intervals for a single proportion. Explain why it is possible for the conclusion of a hypothesis test done at significance level 0.05 to be different from the inference drawn from a 95% confidence interval that is constructed from the same data used to conduct the test.

The Martin County Health Department needs to estimate the proportion of all children in the county aged 19-35 months that are completely up to date with all state-recommended immunizations. The Martin County Health Department found that 88% of a random sample of children in the county aged 19-35 months were completely up to date with all state-recommended immunizations. Find three different confidence intervals - one with sample size 228, one with sample size 402, and one with sample size 658. Assume that 88% of the children each sample are completely up to date with all state recommended immunizations. Observe how the sample size affects the margin of error and subsequently the width of each interval. Report confidence interval solutions using interval notation. Report all solutions in percent form, rounded to two decimal places, if necessary. • When n = 228, the margin of error for a 95% confidence interval is given by When n = • When n = When n = 228, a 95% confidence interval is…

Interpret the 95% confidence interval in context in one sentence.  Does your confidence interval capture 0? Answer this question and discuss what that means in relation to a two-sided hypothesis test. Specifically, do these results allow us to infer anything about the claim stated in the problem? Are the results practically significant? Should the company that created Medicine A stand behind their claim of being non-drowsy based on these results? Answer this question in one or two sentences.

Suppose we know that a confidence interval for a population proportion is (0.105,0.355), with a sample proportion of p̂=0.23. What is the margin of error?

Suppose that Tom and Jerry determine confidence intervals using the same confidence level, based on the same sample proportion. Tom uses a larger sample size than Jerry. How will the midpoint and width of the confidence intervals compare? Same midpoint and same width   Same midpoint, Tom has a wider interval   Same midpoint, Jerry has a wider interval   Same width, Tom has a larger midpoint   Same width, Jerry has a larger midpoint   Tom has a larger midpoint, wider interval   Jerry has a larger midpoint, wider interval

Stanford University conducted a study of whether running is healthy for men and women over age 50. During the first eight years of the study, 1.5% of the 451 members of the 50-plus Fitness Association died. We are interested in the proportion of people over 5o who ran and died in the same eight-year period.   Construct a 95% confidence interval for the population proportion of people over 50 who ran and died in the same eight-year period. Explain in a complete sentence what the confidence interval means

11. In professional tennis for 2017 men challenged 2100 calls and 1105 of them were changed. While women challenged 1309 calls and 625 of them were changed. Find a 95% confidence interval for the difference in changed calls for men and women. 12. For problem # 11 conduct a hypothesis test to test the claim that men get more calls changed than women. Use a significance level of .05. 14. Find a 99% confidence interval for the difference in males and females BMI using the following sample data.Female BMI: n=70, mean=29.1, Sx=7.39.Male BMI: n=80, mean=28.38, Sx=5.37.

Two different simple random samples are drawn from two different populations. The first sample consists of 40 people with 20 having a common attribute. The second sample consists of 1800 people with 1291 of them having the same attribute. Compare the results from a hypothesis test p1=p2 (with a 0.05 significance level) and a 95% confidence interval estimate of p1-p2. What are the null and alternative hypotheses for the hypothesis​ test?

in a poll, 73% of California adults (367 out of 506 surveyed) believe that education is one of the main issues facing California. We want to construct a 90% confidence interval for the true proportion of California adults who believe that education is one of the main issues facing California.-  I need help with finding a 90% confidence interval for the population proportion (I also have to round the answer to three decimal places)

In the Star and Tribune newspaper, there is an article entitled "1 in 8 school buses fail tests." The article says that the overall statewide proportion of school buses that fail safety tests is 9%. However, one bus company has a higher rate of over 12%. Assume that we want a new estimate for the statewide proportion of school buses that fail the safety inspection. How large a sample would you have to take in order to construct a 95% confidence interval estimate for the true proportion of buses that fail the inspection and achieve a margin of error of plus or minus 2%? (your answer should be an integer)