Suppose that the amount of caffeine (in milligrams) in an 16 fluid ounce energy drink can be modeled by the Normal Distribution with a mean of 250 mg and a standard deviation of 70 mg. What is the caffeine content of the 70th percentile of energy drinks? Interpret this value. The 70th percentile is 287 mg. This means that 70% of energy drinks will have caffeine less than or equal to 287 mg. The 70th percentile is 287 mg. This means that 70% of energy drinks will have caffeine greater than or equal to 287 mg. The 70th percentile is 213 mg. This means that 70% of energy drinks will have caffeine greater than or equal to 213 mg. The 70th percentile is 213 mg. This means that 70% of energy drinks will have caffeine less than or equal to 213 mg.

the PDF of normal distribution is = 1/σ * √2π * e ^ -(x-u)^2/ 2σ^2standard normal distribution is a…

Answered: Suppose that the amount of caffeine (in milligrams) in an 16 fluid ounce energy drink can be modeled by the Normal Distribution with a mean of 250 mg and a…

MATLAB: An Introduction with Applications

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Question

Suppose that the amount of caffeine (in milligrams) in an 16 fluid ounce energy drink can be modeled by the Normal Distribution with a mean of 250 mg and a standard
deviation of 70 mg. What is the caffeine content of the 70th percentile of energy drinks? Interpret this value.
The 70th percentile is 287 mg. This means that 70% of energy drinks will have caffeine less than or equal to 287 mg.
The 70th percentile is 287 mg. This means that 70% of energy drinks will have caffeine greater than or equal to 287 mg.
The 70th percentile is 213 mg. This means that 70% of energy drinks will have caffeine greater than or equal to 213 mg.
The 70th percentile is 213 mg. This means that 70% of energy drinks will have caffeine less than or equal to 213 mg.

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