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Suppose that f(t) = sin(3t). Part A. The function g(t) is f(t) shifted to the right 3 units. What is the equation g(t)? Part B. How is the graph of g(t) = 2sin(2t+4) related to f(t) = 2sin(2t)? %3D %3D

Suppose that f(t) = sin(3t). Part A. The function g(t) is f(t) shifted to the right 3 units. What is the equation g(t)? Part B. How is the graph of g(t) = 2sin(2t+4) related to f(t) = 2sin(2t)? %3D %3D

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Suppose that f(t) = sin(3t). Part A. The function g(t) is f(t) shifted to the right 3 units. What is the equation of g(t)? Part B. How is the graph of g(t) = 2sin(2t+4) related to f(t) = 2sin(2t)? %3D
Transcribed Image Text:Suppose that f(t) = sin(3t). Part A. The function g(t) is f(t) shifted to the right 3 units. What is the equation of g(t)? Part B. How is the graph of g(t) = 2sin(2t+4) related to f(t) = 2sin(2t)? %3D
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the base function is 

f\left(t\right)=\sin \left(3t\right)

now the function f(t) shifted right by 3 units

so the new function is given by

g(t)=f(t-3)

g(t)=\sin(3(t-3))

{\color{Red} g(t)=\sin(3t-9)}.

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