Suppose that ƒ is a function given as f(x) = √−3x+5. Simplify the expression f(x + h). f(x + h) = Simplify the difference quotient, - f(x + h) − f(x) h = f(x + h) − f(x) h Rationalize the numerator in the difference quotient. (If applies, simplify again.) f(x + h) − f(x) h The derivative of the function at x is the limit of the difference quotient as h approaches zero. f'(x)=lim h→0 f(x + h) − f(x) h =

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.4: Definition Of Function
Problem 51E
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Suppose that f is a function given as f(x) = √√-3x + 5.
Simplify the expression f(x + h).
f(x + h) =
Simplify the difference quotient,
f(x + h) − f(x)
h
=
f(x + h) − f(x)
h
Rationalize the numerator in the difference quotient. (If applies, simplify again.)
f(x+h) − f(x)
h
-
The derivative of the function at x is the limit of the difference quotient as h approaches zero.
f'(x)=lim
h→0
f(x + h) − f(x)
h
=
Transcribed Image Text:Suppose that f is a function given as f(x) = √√-3x + 5. Simplify the expression f(x + h). f(x + h) = Simplify the difference quotient, f(x + h) − f(x) h = f(x + h) − f(x) h Rationalize the numerator in the difference quotient. (If applies, simplify again.) f(x+h) − f(x) h - The derivative of the function at x is the limit of the difference quotient as h approaches zero. f'(x)=lim h→0 f(x + h) − f(x) h =
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