MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
3.
Suppose that a random sample of 50 cans of a particular brand of fruit juice is selected, and the amount of juice (in ounces) in each of the cans is determined. Let ? denote the mean amount of juice for the population of all cans of this brand. Suppose that this sample of 50 results in a 95% confidence interval for ? of
(7.4, 8.8).
(a)
Would a 90% confidence interval have been narrower or wider than the given interval? Explain your answer.
A 90% confidence interval would have been narrower because the t critical value for 90% confidence is smaller than the t critical value for 95% confidence for the same sample size .A 90% confidence interval would have been narrower because the t critical value for 90% confidence is larger than the t critical value for 95% confidence for the same sample size. A 90% confidence interval would have been wider because the t critical value for 90% confidence is smaller than the t critical value for 95% confidence for the same sample size.A 90% confidence interval would have been wider because the t critical value for 90% confidence is larger than the t critical value for 95% confidence for the same sample size.
(b)
Consider the following statement: There is a 95% chance that ? is between 7.4 and 8.8. Is this statement correct? Why or why not?
The statement is correct. The population mean, ?, is not a constant, and therefore, we can talk about the probability that it falls within a certain interval.The statement is correct. The population mean, ?, is a constant, and therefore, we can talk about the probability that it falls within a certain interval. The statement is not correct. The population mean, ?, is not a constant, and therefore, we cannot talk about the probability that it falls within a certain interval.The statement is not correct. The population mean, ?, is a constant, and therefore, we cannot talk about the probability that it falls within a certain interval.
(c)
Consider the following statement.
If the process of selecting a random sample of size 50 and then calculating the corresponding 95% confidence interval is repeated 100 times, exactly 95 of the resulting intervals will include ?.
Is this statement correct? Why or why not?
The statement is correct. Since it is repeated more than 30 times, we can say that in 100 such samples, exactly 95 will result in confidence intervals that contain ?.The statement is correct. Since the sample size is large, we can say that in 100 such samples, exactly 95 will result in confidence intervals that contain ?. The statement is not correct. We can only say that on average 95 out of every 100 samples will result in confidence intervals that will contain ?.The statement is not correct. We can only say that on average 5 out of every 100 samples will result in confidence intervals that will contain ?.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- С. Consider another brand C of car tyres. From a random sample of 36 car tyres, it has been found that 26 of these car tyres last longer than 40,000 km. Find a 95% confidence interval corresponding to the sample proportion of brand C car tyres which last longer than 40,000 km. Give values correct to three decimal places.arrow_forwardSuppose that the average time spent per day with digital media several years ago was 3 hours and 42 minutes. For last year, a random sample of 20 adults in a certain region spent the numbers of hours per day with digital media given in the accompanying table. Preliminary data analyses indicate that the t-interval procedure can reasonably be applied. Find and interpret a 95% confidence interval for last year's mean time spent per day with digital media by adults of the region. (Note: x=5.49 hr and s=2.20 hr.)arrow_forwardA district official intends to use the mean of a random sample of 150 sixth graders from a very large school district to estimate the mean score that all the sixth graders in the district would get if they took a certain arithmetic achievement test. If, based on experience, the official knows that = 9.4 for such data, suppose that the district official takes her sample and gets = 61.8. Use all the given information to construct a 99% confidence interval for the mean score of all the sixth graders in the district.arrow_forward
- The manager at a large fitness center keeps track of the amount of time it takes a sample of 65 clients to run a mile. She finds that the mean time to run a mile in this sample is x = 10.4 minutes and the standard deviation is s = 2.1 minutes. Assuming the sample is a simple random sample of all clients at this particular fitness center, find a 95% confidence interval H, the unknown mean running time of all clients from the fitness center. for (Give your answer as an interval in the form (lower limit, upper limit). Use decimal notation. Give the limits to two decimal places.) 95% confidence interval:arrow_forward6.2.13 Use the given confidence interval to find the margin of error and the sample mean. (14.2,24.0) The sample mean is (Type an integer or a decimal.)arrow_forward56.A random sample of 40 companies with assets over $10 million was surveyed and asked to indicate their industry and annual computer technology expense. The ANOVA comparing the average computer technology expense among three industries rejected the null hypothesis. The Mean Square Error (MSE) was 195. The following table summarized the results: Based on the comparison between the mean annual computer technology expense for companies in the tax service and food service industries, the 95% confidence interval shows an interval of -5.85 to 14.85 for the difference. This result indicates that _______________. A.There is no significant difference between the two industry technology expenses B.The interval contains a difference of 20.7 C.Companies in the food service industry spend significantly more than companies in the tax service industry D.Companies in the food service industry spend significantly less than companies in the tax service industryarrow_forward
- 3. A researcher has collected the blood samples of 29 individuals and found that the mean hemoglobin concentration for the sample of individuals is 13.9 grams per deciliter and the standard deviation is 1.43 grams per deciliter. Calculate a 95% confidence interval for the mean hemoglobin concentration for the population.A) (13.36, 14.44)B) (13.38, 14.42)C) (10.98, 16.82)D) (11.10, 16.70)arrow_forwardSuppose that x = 11 observations possess the characteristic of interest from n = - 32 observations. Let p be the population proportion possessing the characteristic. (a) Compute a two-sided 99% confidence interval for p. (b) Compute a two-sided 95% confidence interval for p.arrow_forwardJelly beans are packed in boxes of 50, and the overall proportion of black jelly beans is set by the manufacturer to be 0.2. Suppose that 10 boxes of jelly beans are selected at random, and the proportion of black jelly beans in each box determined. a Use your calculator to generate 10 values of the sample proportidn p of black jelly beans in a box. b Use your calculator to find an approximate 80% confidence interval for the population proportion p from each of these values of the sample proportion p. c How many of these intervals contain the value of the population proportion p? d How many of these intervals would you expect to contain the value of the population proportion p? e Suppose that we generate 50 approximate 80% confidence intervals for p. How many of these intervals would you expect to contain the value of the population proportion p?arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman
MATLAB: An Introduction with Applications
Statistics
ISBN:9781119256830
Author:Amos Gilat
Publisher:John Wiley & Sons Inc
Probability and Statistics for Engineering and th...
Statistics
ISBN:9781305251809
Author:Jay L. Devore
Publisher:Cengage Learning
Statistics for The Behavioral Sciences (MindTap C...
Statistics
ISBN:9781305504912
Author:Frederick J Gravetter, Larry B. Wallnau
Publisher:Cengage Learning
Elementary Statistics: Picturing the World (7th E...
Statistics
ISBN:9780134683416
Author:Ron Larson, Betsy Farber
Publisher:PEARSON
The Basic Practice of Statistics
Statistics
ISBN:9781319042578
Author:David S. Moore, William I. Notz, Michael A. Fligner
Publisher:W. H. Freeman
Introduction to the Practice of Statistics
Statistics
ISBN:9781319013387
Author:David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:W. H. Freeman