Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500 randomly selected adult residents in this city are surveyed to determine whether they have cell phones. Of the 500 people surveyed, 421 responded yes – they own cell phones. a) Using a 90% confidence level, compute a confidence interval estimate for the percentage of all adults in this large city who have cell phones. b) Using the sample data, what is the minimum sample size needed so that the margin of error in a 90% confidence interval is less than 0.01?

Q: In a survey of 2591 adults in a recent​ year 1414, say they have made a New​ Year's resolution.…

A: From the provided information,Confidence level = 90% and 95%

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: mey currently use social media. Use the data from this survey to construct a 94% confidence interval…

A: The sample size is n = 2821 And number of social media users = 1657 At 94% confidence level, the…

Q: What is the distinction between independent and dependent samples in hypothesis testing involving…

A: The objective is to determine the distinction between independent and dependent samples in…

Q: confidence inferval for the actual percentage of students who want to pursue a college course.…

A: here from given  n = sample size  = 600 x= no of student expressed interest to purchase a college…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: A bank randomly selected 200 checking-account customers and found that 110 of them also had savings…

A: Given that A bank randomly selected 200 checking-account customers and found that 110 of them also…

Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: Construct a 95% confidence interval for the difference between population proportion of voters in…

A:

Q: When 302 college students are randomly selected and surveyed, it is found that 122 own a car. What…

A: E have to find point estimate with with confidance interval..

Q: Jane

A:

Q: In a survey of 2542 adults in a recent​ year, 1487 say they have made a New​ Year's resolution.…

A: Given,  n = 2542 x = 1487 proportion p  = 1487/2542                       = 0.5850

Q: 4. Assume that 66 % of single women and 81.9% of single men own cars. Also assume that these…

A: From the provided information,

Q: We want to estimate the proportion of vegetarian restaurants in a country. We observe 20 such…

A: We observe 20 such restaurants out of 100 p⏞ =xn=20100=0.5 90% confidence interval for the…

Q: Jane wants to estimate the proportion of 13 students on her campus 4 who eat cauliflower. After…

A:

Q: You recently sent out a survey to determine if the percentage of adults who use social media has…

A: It is given that sample size (n) is 2,461 and x is 1,702.

Q: A study by researchers at a university addressed the question of whether the mean body temperature…

A: Given that, A study by researchers at a university addressed the question of whether the mean body…

Q: You recently sent out a survey to determine if the percentage of adults who use social media has…

A: We have to find the confidence interval for population proportion (p) CI = p^ ±zα/2p^(1-p^)n Where,…

Q: Of 219 employees selected randomly from a company, 10% of them commute by carpooling. Construct a…

A: Given Data Sample Size, n = 219 Sample proportion = p̂= 0.10 Significance level, α…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A:

Q: Seventy-three percent of a sample of 1000 students drive a used car as opposed to a new car or no…

A: Given: Proportion  = 73 % Confidence level  = 80 %

Q: According to this equation, what is the predicted value of the dependent variable when the…

A:

Q: recently sent out a survey to determine if the percentage of adults who use social media has changed…

A: The value of z at 96% confidence level is 2.054, which can be obtained by suing the standard normal…

Q: Out of 54 randomly selected patients of a local hospital who were surveyed, 42 reported that they…

A: Given that, The total patients n are 54 and the total patients who were satisfied x are 42.

Q: The Harvard school of public health conducted a survey of 2770 adults in the United States to…

A: It is given that sample size n is 2,770 and p hat is 0.26.The point estimate for population…

Q: In a survey conducted by a reputable marketing agency, 231 of 1000 adults 19 years of age or older…

A: Given Data Sample Size, n = 1000 Number of successes, x = 231.0 Significance…

Q: Use the data from this survey to construct a 91% confidence interval estimate of the proportion of…

A:

Q: was the percentage of adults who used social media five years ago. Of the 2703 people who responded…

A: (a) The sample proportion is: p= x/n=1758/2703 =0.65 The value of z at 92% confidence level is 1/75,…

Q: In a poll, 1000 randomly selected adults are surveyed and 250 of them support a certain social…

A: Solution: 4. a. Let X be the number of adults support a certain social program and n be the sample…

Q: In a survey of 2588 ​adults, 1466 say they have started paying bills online in the last year.…

A: Construct 99% confidence interval for population proportion:The sample of 2,588 adults among that…

Q: A random sample of 400 people is selected from Atlantic Canada. They are asked about their views on…

A: According to the given information, we have Given that a random sample of 400 people is selected…

Q: In a random sample of 230 men , 18 or older , 142 were married. Construct and explain a 90%…

A: Solution: Let X be the number of married men 18 or older and n be the sample number of men. From the…

Q: Construct a 95% confidence interval for the population proportion of students who graduate within…

A: The sample size is n = 400 And the number of students who graduate within six years, X = 108 The…

Q: Out of 42738 freshmen entering the State University system,  27298 of them need to take remedial…

A:

Q: In one state, of 927 fatalities, 632 were alcohol-impairing-driving related. Construct the 95%…

A:

Q: What proportion of commercial airline pilots are more than 40 years of age? Suppose an analyst has…

A: Let p be the population proportion of commercial airline pilots who are more than 40 years of…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.