Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to keep in stock. At the end of one year, the store used the weekly sales information to construct a 95% confidence interval for the mean number of emeralds sold per week. The confidence interval they calculated was (3.25,4.51). Use the confidence interval to find the point estimate for the mean and the margin of error. Give your answers precise to two decimal places.

Q: e: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the…

A: Sample size n =47 Sample mean=109 Population standard deviation =32

Q: The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish…

A: Answer  Given  Sample mean =244 population standard deviation=15 sample size =50 Confidence interval…

Q: In 2016 the CDC wanted to estimate the proportion of adults who are smokers in the U.S. The…

A:

Q: You are interested in finding a 95% confidence interval for the mean number of visits for physical…

A: Given,mean(x¯)=13.6standard deviation (s)=9.1918sample size(n)=10degrees of…

Q: A research scientist wants to know how many times per hour a certain strand of bacteria reproduces.…

A:

Q: n = 260 and X = 208, construct a 90% confidence interval for the population proportion, p. Give…

A: Given data,x=208n=260p^=xn=208260=45=0.80

Q: f n=450 and X = 360, construct a 99% confidence interval.

A:

Q: Translate the statement into a confidence interval. Approximate the level of confidence.   In a…

A: Determine the confidence interval for the proportion. Thus, the confidence interval lies between…

Q: If n=30, (x-bar)=38, and s=8, construct a confidence interval at a 90% confidence level. Assume the…

A:

Q: Use the data about the sample to calculate a 95% confidence interval for the average income of…

A: 1. The conditions for using t-distribution are: Sample size is small. Population standard deviation…

Q: A person surveyed his Youtube chat and asked how many pages of manga of Demon Slayer they have seen.…

A: The mean number of episodes was 304 episodes. The confidence interval for the population mean is,…

Q: A poll of 1060 adults in a country was conducted by telephone. Of those surveyed, 169 had…

A: The sample size is 1060 and number of success is 169.

Q: In 2011 the U.S. Department of Transportation reported with 95% confidence that the average length…

A: We have to find confidence Iinterval

Q: A successful basketball player has a height of 6 feet 8 ​inches, or 203 cm. Based on statistics from…

A: Consider X is a random variable defined as the height of a successful basketball player.The provided…

Q: Let {N(t), t = [0, ∞)} be a Poisson process with rate x. Let T₁, T2, be the arrival times for this…

A: According to the question,

Q: find the point estimate for the mean and the margin of error. Give your answers precise to two…

A: Given Data Lower limit = 1.97 upper limit = 2.93

Q: A statistics practitioner took a random sample of 56 observations from a population whose standard…

A: We have given that,  Sample size (n) = 56, population standard deviation (σ) = 35 and sample mean…

Q: sample of 35 students was taken from the local university. These students spent an average of $180…

A:

Q: How much more likely are college men than college women to participate in intramural sports?  A…

A: Given information: Number of college men surveyed, n1=688 Number of college women surveyed, n2=579…

Q: Mark each statement TRUE or FALSE. For these problems, assume that to estimate average time spent…

A: The 95% confidence interval is (4,6).

Q: A statistics practitioner took a random sample of 48 observations from a population whose standard…

A: sample size(n)=48 population standard deviation(σ)=25 Mean(x)=105

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A: Given X=25 n=500 95% confidence interval

Q: The marketing director concluded, with 95% confidence, that between $113.36 and $130.64 contains the…

A: Given: Sample size,n=40Sample mean x¯=122Sample standard deviation s=27confidence level,c =95% =…

Q: A statistics practitioner took a random sample of 43 Note: For each confidence interval, enter your…

A: n = 43 standard deviation = 27 mean = 104 95% confidence interval for mean is given by  x±zα2*σn 104…

Q: A statistics practitioner took a random sample of 55 observations from a population whose standard…

A: It is given that, Sample mean = 104. Population standard deviation, sigma is 31. The sample size, n…

Q: atistics practitioner took a random sample of 49 observations from a population whose standard…

A: Sample size n =49 Sample mean=103 Population standard deviation =25

Q: lculating the confidence interval.

A: x Freq 1 3 2 5 3 19 4 7 5 6 Total 40

Q: If n 28, = 37, and s = 6.2, construct a confidence interval at a 97% confidence level. Assume the…

A: Solution: The following information is given to us: s=6.2 n =28 A 97% confidence interval is…

Q: Critical Value: Margin of Error: Lower Bound: Upper Bound: Interpret (context) OEM C *2 decimals *2…

A: * Hi! Thank you for the question As per the honour code, We’ll answer the first question since the…

Q: If n=14, (x-bar)=46, and s=18, construct a confidence interval at a 80% confidence level. Assume the…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: A toy manufacturer wants to know how many new toys children buy each year. A sample of 242 children…

A:

Q: magine that you conduct a study and estimate that the prevalence of hypertension among employees of…

A: From the provided information, Sample proportion (p̂) = 0.24 Margin of error for a 95% confidence…

Q: Determine the point estimate of the population mean and margin of error for the confidence interval.…

A: Given,lower bound=21upper bound=29

Q: Find a Confidence interval for the true Population Proportions if n = 30,        x = 75, and the…

A: From the given information, X=75 and n=30.

Q: Express the form of most of the confidence intervals that you will encounter in your study of…

A: Confidence Interval:Confidence interval is the interval estimate of the population parameter. It is…

Q: Mark each statement TRUE or FALSE. For these problems, assume that to estimate average time spent…

A: It is given that the sample size is 10.

Q: Construct a 90% confidence interval for the mean when x̅=50 and there are 31 observations. Suppose…

A:

Q: A statistics practitioner took a random sample of 47 observations from a population whose standard…

A: Given that  Sample size n =47 Sample mean =97 Population standard deviation =32

Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a…

A:

Q: A statistics practitioner took a random sample of 59 observations from a population whose standard…

A: sample size(n)=59 Population standard deviation(σ)=32 Mean(x)=95

Q: A recent survey conducted in a nearby town showed that 791 out of 1,495 people do most their holiday…

A: Here, the sample proportion is =7911495=0.5291 Now, for 90% confidence z=1.645

Q: The dean randomly selected 33 students who took the calculus final exam and looked at their scores…

A: