Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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- The equilibrium constant, K, for the following reaction is 2.53×10-2 at 519 K. PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture of the three gases in a 17.8 L container at 519 K contains 0.233 M PCl5, 7.68×10-2 M PCl3 and 7.68×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 8.95 L? [PCl5] = M [PCl3] = M [Cl2] = Marrow_forwardThe equilibrium constant, K, for the following reaction is 1.0 x 10 -5 at 1500 K. N2(g) + O2(g) <---> 2 NO(g) If 0.750 M N2 and 0.750 M O2 are allowed to reach equilibrium at 1500 K, what is the concentration of NO? a. 2.4 x 10-3M b. 6.7 x 10-4M c. 5.5 x 10-3M d. 2.7 x 10-3M e. 1.2 x 10-3Marrow_forward1. Carbon dioxide reacts with carbon to give carbon monoxide according to the equation C(s) + CO,(g) 2CO(g) At 700°C, a 2.0-L sealed flask is found to contain at equilibrium 0.10 mol CO, 0.20 mol CO, and 0.40 mol C. Calculate the equilibrium constant K, for this reaction at the specified temperature.arrow_forward
- CO(g) + H₂O(g) ⇒ H₂(g) + CO₂(g) K = 7.3@823 K A closed 5.0 L container initially holds 3.0 moles CO and 6.0 moles H2O. Calculate the concentrations of each material at equilibrium. What is the equilibrium concentration of H₂O? [H₂O] = [?] Marrow_forwardConsider the following reaction at a certain temperature: 4 Fe(s) + 3 O2(g)→ 2 Fe203(s) An equilibrium mixture contains 1.2 mol Fe, 0.00090 mol O2, and 2.0 mol Fez03 all in a 2.0-L container. Calculate the value of K for this reaction. K =arrow_forwardHydrogen iodide decomposes according to the reaction 2HI(g) = H₂(g) + 1₂ (g) A sealed 1.50-L container initially holds 0.00623 mol of H₂, 0.00414 mol of 1₂, and 0.0244 mol of HI at 703 K. When equilibrium is reached, the concentration of H₂(g) is 0.00524 M. What are the equilibrium concentrations of HI (g) and I₂ (g)? Round each of your answers to 3 significant figures. Part 1 of 2 [HI] = M Part 2 of 2 [¹2]eq = M x10 x10 X x Ś Sarrow_forward
- Explain step by steparrow_forward6. Hydrogen gas is finding more acceptance as an alternative fuel. It is produced along with carbon dioxide by the reaction of carbon monoxide and gaseous water at 915 K. At this temperature, the equilibrium constant (K.) is 1.56. If this reaction is started in a 4.00 L closed system flask with 0.450 mol of CO, 1.25 mol H2O, 1.15 mol CO2, and 3.50 mol H2, calculate the concentrations of all substances in the flask initially and at equilibrium. Put these values in the ICE table below. (Hint: you will need to use the quadratic formula.) CO Н20 CO2 H2 INITIAL CHANGE EQUILIBRIUM 0.1125 0.3125 0.2875 0.875 -X -X +X +x e these values in the table. d. Calculate the reaction quotient, Q. e. Express the direction of equilibrium shift as an algebraic expression. Complete the change row of the table. f. Substitute the algebraic expressions into the equilibrium expression and solve for the equilibrium concentrations. Place these values in the table.arrow_forwardConsider the reaction A + B C+D, which has an equilibrium constant, K, equal to 3.4 x 102. If one begins a reaction by placing 0.600 moles of A in a 1.0 L container as well as 0.150 moles of 1. B, what will be the equilibrium concentrations of A, B, C, and D? Write your answers in the spaces provided below. a. [А] b. [B]= [C]= С. d. [D]= Once the reaction in problem 1 reaches equilibrium, some additional B is injected into the flask 2. from an outside source. LeChatelier's principle says the reaction will (circle one): be unchanged shift to the right shift to the left Pyridine is a weak base with a Kb 1.7 x 109. If 0.300 moles of pyridine is added to 1.00 L of 3. water, what will be the equilibrium concentrations of the species below: a. [Pyridine] = b. [Pyridine-H] (the pyridinium ion) [ОН-] 3 С. What is the pH of the solution in problem 4 (above)? .arrow_forward
- 11. At a certain temperature, the equilibrium constant K for the following reaction is 9.0 x 10-8: N₂(g) + O₂(g) 2 NO(g) L Use this information to complete the following table. Suppose a 22. L reaction vessel is filled with 1.1 mol of NO. What can you say about the composition of the mixture in the vessel at equilibrium? What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 2 NO(g) N₂(9) + O₂(9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. 3 N₂(9)+30₂(9) 6 NO(g) Explanation # acBook Pro Check O There will be very little N₂ and 0₂. O There will be very little NO. O Neither of the above is true.. K = 0 K = 0 © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center → a x10 alo Accessibility Ararrow_forwardAt a certain temperature, the equilibrium constant, K., is 0.00572 for the reaction Cl,(g) = 2 Cl(g) A. If 2.77 g Cl, is placed in a 2.50 L flask at this temperature, what are the equilibrium concentrations of Cl, and Cl? [CI,] = M [CI] = M B. Following the establishment of equilibrium in part A, the volume of the flask is suddenly increased to 5.00 L while the temperature is held constant. What are the new equilibrium concentrations of Cl, and Cl? [Cl,] = M [CI] = M C. Following the establishment of equilibrium in part A, the volume of the flask is instead suddenly decreased to 1.0 L while the temperature is held constant. What are the new equilibrium concentrations of Cl, and CI? [Cl,] = M [CI] = Marrow_forward
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