Suppose that 0.1 kg of ice at an initial temperature of -10degree celcius are put into 0.40kg of water at an initial temperature of 20 degree celcius.Assume the final temperature is 0 degree celcius. How many grams of ice will melt? Specific heat capacity of water is 4200J/kg/degree celcius, specific heat of fusion of water is 346000J/kg and specific heat capacity of ice is 2100J/kg/degree celcius

When a material changes phase - liquid, solid, gas- heat exchange is required. This heat is called the Latent heat. is the equation where L is the Latent heat and is material specific. How much heat is required to take water (mass of .55 kg) from -20 to 20 C? L for ice to water is 33.5 * 104 J/kg. the specific heat of ice is 2090 J/(kg*C).and for water is 4186 J/(kg*C).

Calculate the rate of heat conduction through house walls that are 13.0 cm thick and that have an avera thermal conductivity of 0.027W/m°C. Assume there are no windows or doors. The surface area of the walle is 120m? and their inside surface is at 18.0°C, while their outside surface is at 5.00°c

A cube of ice is taken from the freezer at -9.5 °C and placed in a 95-g aluminum calorimeter filled with 300 g of water at room temperature of 20.0 °C. The final situation is observed to be all water at 16.0 °C. The specific heat of ice is 2100 J/kg · C°, the specific heat of aluminum is 900 J/kg · C°, the specific heat of water is is 4186 J/kg·C°, the heat of fusion of water is 333 kJ/Kg. Part A What was the mass of the ice cube? Express your answer to two significant figures and include the appropriate units. ? Value Units m = Submit Request Answer

What is the ratio of the energy required to warm 125 g of Ice (0.0 \deg C) to body temperature (37 \deg C) to warming the same amount of water through the same temperature change? Answer format is the number Eice/Ewater = (2 significant figures) Latent Heat of Fusion of Water: 335, 000 J/kg Specific Heat Capacity of Water: 4186 J/kg/\deg C

Suppose a house's walls are 13.5 cm thick and and have an average thermal conductivity twice that of glass wool. Given: Thermal Conductivity of glass wool= 0.042k Calculate the rate of heat conduction, in watts, through the house's walls. Assume there are no windows or doors. The surface area of the walls is 120 m2 and their inside surface is at 16°C, while their outside surface is at 5.15°C .