suppose an nxn matrix has positive diagonal entries and negative everywhere else. suppose sum of the entries in each row are positve. prove det(A) is not 0.
suppose an nxn matrix has positive diagonal entries and negative everywhere else. suppose sum of the entries in each row are positve. prove det(A) is not 0.
Chapter7: Systems Of Equations And Inequalities
Section7.7: Solving Systems With Inverses
Problem 5SE: Can a matrix with zeros on the diagonal have an inverse? If so, find an example. If not, prove why...
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Question
suppose an nxn matrix has positive diagonal entries and negative everywhere else. suppose sum of the entries in each row are positve. prove det(A) is not 0.
Expert Solution
Step 1
Introduction:
To prove that the determinant of matrix A is non-zero, we will show that A is invertible. If A is invertible, then its determinant is non-zero because det(A) is the product of its eigenvalues, and since all eigenvalues of A are non-zero, det(A) must also be non-zero.
Given:
nxn matrix has positive diagonal entries and negative everywhere else.
We need to prove that det(A) is not 0.
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