Suppose a simple random sample of size n= 1000 is obtained from a population whose size is N=2,000,000 and whose population proportion with a specified characteristic is p%=0.54. Complete parts (a) through (c) below.(a) Describe the sampling distribution of p.O A. Approximately normal, u = 0.54 and o s0.0158B. Approximately normal, uA=0.54 and oA0.0002O C. Approximately normal, u = 0.54 and on 0.0004(b) What is the probability of obtaining x =570 or more individuals with the characteristic?P(x2570)=759 (Round to four decimal places as needed.)(c) What is the probability of obtaining x 520 or fewer individuals with the characteristic?P(xs 520)= Round to four decimal places as needed.)WoteClick to select your answer(s).O Type here to searchF12InsertPrntScrF9F10F11F6F7F8F504F2F3F4EscF1BIDBacC@24&56* CO

From the provided information, Sample size (n) = 1000 Proportion (p) = 0.54 a) According to central…

Answered: Suppose a simple random sample of size…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Calculate the variance for the distribution given in the attached, A. 429.84 / B. 492.98 / C. 924.86 / D. 942.99
Suppose the age distribution of the Canadian population and the age distribution of a random sample of 491 residents in the Indian community of Red Lake are shown below. Observed Number Age (years) Percent of Canadian Population in Red Lake Village Under 5 5.8% 14 5 to 14 10.0% 46 15 to 64 73.8% 371 65 and older 10.4% 60 Use a=0.05 to test the claim that the age distribution of the general Canadian population fits the age distribution of the residents of Red Lake Village. State the null and alternate hypotheses. Group of answer choices The distributions are not equal to zero ; The distributions are not the same. The distributions are the same; The distributions are not the same. The distributions are not equal to zero; The distributions are equal to zero. The distributions are different; The distributions are not equal to zero. The distributions are equal to zero; The distributions are the same.
A random sample is to be selected from a population that has a proportion of successes p = 0.64. Determine the mean and standard deviation of the sampling distribution of p̂ for each of the following sample sizes. (Round your standard deviations to four decimal places.) a. n = 30 mean: standard deviation: b. n = 40 mean: standard deviation: c. n = 50 mean: standard deviation:
Solve for C)
Histograms of random sample data are often used as an indication of the shape of the underlying population distribution. The histograms on the next page are based on random samples of size 30,50 and 100 from the same population. a. Using the midpoint labels of the three histograms, what would you say about the estimated range of population data from smallest to largest? Does the bulk of the data seem to be between 8 and 12 all in three histograms? b. The population distribution from which the samples were drawn is symmetric and mound shaped, with the top of the mound at 10,95% of the data between 8 and 12, and 99.7% of data between 7 and 13. How well does each histogram reflect these characteristics?
As the sample size (n) increases, does the sampling distribution of the sample mean stay the same, look more and more like a uniform distribution, or become more tightly clustered around the population mean?
1. Consider a normal distribution with mean u mean. Calculate 12. Let ī be the sample P(i > 36) for each of the following cases: (a) n = 9, a = 90; (b) n = 9, s = 102; (c) n = 16, o = 80; and (d) n = 16, s = 71.6.
For a normal-shaped distribution with µ = 50 and σ = 8: a) What proportion of the scores have values between 46 and 54? b) For samples of n = 4, what proportion of the samples means have values between 46 and 54? c) For sample of n = 16, what proportion of the sample mean have values between 46 and 54?
3
The marital status distribution of the U.S male population, age 15 and older, is as shown below in first column. Suppose that a random sample of 400 U.Syound adult males, 18-38 years old, yielded the following frequency distribution . We are interested in whether this age group of males fits the distribution of the U.S adult population. marital status expected frequency observed frequency never marreid 31.3 140 marreid 56.1 238 widowed 2.5 2 divorced/seperated 10.1 20 total 100 400 Choose the correct calculation
4. For the following information, determine whether a normal sampling distribution can be used, where p is the population proportion, α is the level of significance, p is the sample proportion, and n is the sample size. If it can be used, test the claim. Claim: p>0.29; α=0.06. Sample statistics: p=0.36, n=425 Question content area bottom Part 1 Let q=1−p and let q=1−p. A normal sampling distribution ▼ cannot can be used here, since ▼ n ModifyingAbove p with caretnp npnp ▼ less than< greater than or equals≥ 5 and ▼ n ModifyingAbove q with caretnq nqnq ▼ less than< greater than or equals≥ 5.
Step 2 The value of $₁ is the number of non- If mp ₁, ma₁, np₂, and no₂ are at least 10, we can use the large-sample test procedure with an approximately standard normal distribution. The variables m and n are the sample sizes of Brand A and Brand B, respectively, p₁ and 2 are the sample proportions of non- contaminated chickens of Brand A and Brand B, respectively, and ₁ = 1 - ₁ and ₂ = 1 - P₂. Recall that 38 of 80 chickens from Brand A tested positive, so the number of non-contaminated chickens is 80 - 38 = contaminated Brand A chickens divided by the total number of Brand A chickens, or p ₁ = Calculate mp₁. = 80( mp₁ Recall that ₁1 - ₁. Calculate ma₁. ma₁ = 80(1-p₁) 80(1- We are told that 64 of 80 chickens from Brand B tested positive, so the number of non-contaminated chickens is 80 - 64 = P₂ = Calculate np₂. np₂ = 80 Calculate n4₂, where na₂ = 80(1-₂) 80(1 – [ = 1-P₂- The value of 2 is the number of non-contaminated Brand B chickens divided by the total number of chickens of Brand…

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