Suppose a simple random sample of size n= 1000 is obtained from a population whose size is N=2,000,000 and whose population proportion with a specified characteristic is p%=0.54. Complete parts (a) through (c) below. (a) Describe the sampling distribution of p. O A. Approximately normal, u = 0.54 and o s0.0158 B. Approximately normal, uA=0.54 and oA0.0002 O C. Approximately normal, u = 0.54 and on 0.0004 (b) What is the probability of obtaining x =570 or more individuals with the characteristic? P(x2570)=759 (Round to four decimal places as needed.) (c) What is the probability of obtaining x 520 or fewer individuals with the characteristic? P(xs 520)= Round to four decimal places as needed.) Wote Click to select your answer(s). O Type here to search F12 Insert PrntScr F9 F10 F11 F6 F7 F8 F5 04 F2 F3 F4 Esc F1 BID Bac C@ 24 & 5 6 * CO

Histograms of random sample data are often used as an indication of the shape of the underlying population distribution. The histograms on the next page are based on random samples of size 30,50 and 100 from the same population. a. Using the midpoint labels of the three histograms, what would you say about the estimated range of population data from smallest to largest? Does the bulk of the data seem to be between 8 and 12 all in three histograms?  b. The population distribution from which the samples were drawn is symmetric and mound shaped, with the top of the mound at 10,95% of the data between 8 and 12, and 99.7% of data between 7 and 13. How well does each histogram reflect these characteristics?

As the sample size (n) increases, does the sampling distribution of the sample mean stay the same, look more and more like a uniform distribution, or become more tightly clustered around the population mean?

1. Consider a normal distribution with mean u mean. Calculate 12. Let ī be the sample P(i > 36) for each of the following cases: (a) n = 9, a = 90; (b) n = 9, s = 102; (c) n = 16, o = 80; and (d) n = 16, s = 71.6.

For a normal-shaped distribution with µ = 50 and σ = 8: a) What proportion of the scores have values between 46 and 54? b) For samples of n = 4, what proportion of the samples means have values between 46 and 54? c) For sample of n = 16, what proportion of the sample mean have values between 46 and 54?

The marital status distribution of the U.S male population, age 15 and older, is as shown below in first column. Suppose that a random sample of 400 U.Syound adult males, 18-38 years old, yielded the following frequency distribution . We are interested in whether this age group of males fits the distribution of the U.S adult population. marital status expected frequency observed frequency never marreid  31.3 140 marreid 56.1 238 widowed 2.5 2 divorced/seperated 10.1 20 total 100 400 Choose the correct calculation

4. For the following​ information, determine whether a normal sampling distribution can be​ used, where p is the population​ proportion, α is the level of​ significance, p is the sample​ proportion, and n is the sample size. If it can be​ used, test the claim. ​Claim: p>0.29​; α=0.06. Sample​ statistics: p=0.36​, n=425       Question content area bottom Part 1 Let q=1−p and let q=1−p. A normal sampling distribution ▼   cannot can be used​ here, since ▼   n ModifyingAbove p with caretnp npnp ▼   less than< greater than or equals≥ 5 and ▼   n ModifyingAbove q with caretnq nqnq ▼   less than< greater than or equals≥ 5.

Step 2 The value of $₁ is the number of non- If mp ₁, ma₁, np₂, and no₂ are at least 10, we can use the large-sample test procedure with an approximately standard normal distribution. The variables m and n are the sample sizes of Brand A and Brand B, respectively, p₁ and 2 are the sample proportions of non- contaminated chickens of Brand A and Brand B, respectively, and ₁ = 1 - ₁ and ₂ = 1 - P₂. Recall that 38 of 80 chickens from Brand A tested positive, so the number of non-contaminated chickens is 80 - 38 = contaminated Brand A chickens divided by the total number of Brand A chickens, or p ₁ = Calculate mp₁. = 80( mp₁ Recall that ₁1 - ₁. Calculate ma₁. ma₁ = 80(1-p₁) 80(1- We are told that 64 of 80 chickens from Brand B tested positive, so the number of non-contaminated chickens is 80 - 64 = P₂ = Calculate np₂. np₂ = 80 Calculate n4₂, where na₂ = 80(1-₂) 80(1 – [ = 1-P₂- The value of 2 is the number of non-contaminated Brand B chickens divided by the total number of chickens of Brand…