Suppose a 500. mL. flask is filled with 0.10 mol of Cl₂ and 0.50 mol of HCI. The following reaction becomes possible: H₂(g) + Cl₂ (g) → 2HCI(g) The equilibrium constant K for this reaction is 0.204 at the temperature of the flask. Calculate the equilibrium molarity of Cl₂. Round your answer to two decimal places. M X 5

Suppose a 500. mL flask is filled with 1.7 mol of Cl₂, 1.1 mol of CHCl3 and 1.3 mol of HCl. The following reaction becomes possible: Cl₂(g) + CHCl3 (g) → HC1(g) +CC14 (g) The equilibrium constant K for this reaction is 9.41 at the temperature of the flask. Calculate the equilibrium molarity of Cl₂. Round your answer to two decimal places. 10999

Suppose a 250. mL flask is filled with 0.70 mol of Cl₂ and 1.1 mol of HCI. The following reaction becomes possible: H₂(g) + Cl₂(g) 2HCl(g) The equilibrium constant K for this reaction is 0.288 at the temperature of the flask. Calculate the equilibrium molarity of Cl₂. Round your answer to two decimal places. M 1

Suppose a 250. mL flask is filled with 1.5 mol of CO, 0.80 mol of NO and 0.70 mol of CO,. The following reaction becomes possible: 2' NO, (g) +CO(g) - NO(g)+CO,(g) The equilibrium constant K for this reaction is 6.92 at the temperature of the flask. Calculate the equilibrium molarity of NO. Round your answer to two decimal places. olo Ar OM ?

Suppose a 500.mL flask is filled with 1.5mol of CO, 1.1mol of H2O and 1.6mol of H2. The following reaction becomes possible: CO(g)+H2O(g)+CO2(g)+H2(g)   The equilibrium constant K for this reaction is 0.840 at the temperature of the flask. Calculate the equilibrium molarity of CO2. Round your answer to two decimal places.

Suppose a 250. mL flask is filled with 0.70 mol of H2 and 1.1 mol of 12. The following reaction becomes possible: H2(g) +I2(g) — 2HI(g) =0 The equilibrium constant K for this reaction is 8.37 at the temperature of the flask. Calculate the equilibrium molarity of 12. Round your answer to two decimal places. Ом

Suppose a 250. mL flask is filled with 0.60 mol of SO₂ and 1.0 mol of SO3. This reaction becomes possible: 2SO₂(g) + O₂(g) — 2SO3(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O₂. You can leave out the M symbol for molarity. initial change equilibrium SO₂ 0₂ 0 X 0 SO₂ 0 010 X Ś

Suppose a 500. mL flask is filled with 0.30 mol of SO, and 1.2 mol of SO3. This reaction becomes possible: 2SO, (g) +O,(g) 2SO3 Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of O,. You can leave out the M symbol for molarity. so, SO2 O2 initial change equilibrium

Suppose a 500. mL flask is filled with 1.3 mol of Cl₂ and 0.80 mol of HC1. The following reaction becomes possible: H₂(g) + Cl₂(g) → 2HCl (g) The equilibrium constant K for this reaction is 9.14 at the temperature of the flask. Calculate the equilibrium molarity of H₂. Round your answer to two decimal places. M X Ś E A olo 18

Suppose a 500. mL flask is filled with 0.50 mol of N, and 0.90 mol of NO. This reaction becomes possible: N,(8) +O,(g) – 2NO(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N,. You can leave out the Msymbol for molarity. NO initial change equilibrium