Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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**Problem Statement:**

*Suppose 35.7 g of iron(II) iodide is dissolved in 350. mL of a 0.40 M aqueous solution of silver nitrate.*

*Calculate the final molarity of iodide anion in the solution. You can assume the volume of the solution doesn’t change when the iron(II) iodide is dissolved in it.*

*Round your answer to 1 significant digit.*

**Solution Explanation:**

To solve for the final molarity of the iodide anion, follow these steps:

1. **Determine the moles of iron(II) iodide (FeI₂):**
   - Molar mass of FeI₂ = Fe (55.85 g/mol) + 2 * I (126.90 g/mol) = 309.65 g/mol
   - Moles of FeI₂ = mass (35.7 g) / molar mass (309.65 g/mol)
  
2. **Calculate the moles of iodide ions (I⁻) produced:**
   - Each mole of FeI₂ produces 2 moles of I⁻.
   - Moles of I⁻ = moles of FeI₂ * 2

3. **Assumption and Conversion:**
   - The total volume of the solution remains 350 mL (0.350 L).

4. **Determine the final molarity of the iodide ions:**
   - Final molarity (M) = moles of I⁻ / total volume in liters (L)

**Diagram or Graph Explanation:**

This problem does not include any diagrams or graphs. It only involves numerical calculations to determine the molarity of iodide anions in a given solution.

**Interactive Tools:**

On the user interface, several interactive buttons are visible:
- A box to input the answer with units for molarity (M).
- Buttons likely for submission ("X" for cancel, a reset button, and a help button).

**Important Points to Remember:**
- Always account for significant digits in the final answer.
- Pay close attention to the molar masses and conversion between grams and moles.
- Consider the assumption that volume remains constant when solutes are added to a solution.
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Transcribed Image Text:**Problem Statement:** *Suppose 35.7 g of iron(II) iodide is dissolved in 350. mL of a 0.40 M aqueous solution of silver nitrate.* *Calculate the final molarity of iodide anion in the solution. You can assume the volume of the solution doesn’t change when the iron(II) iodide is dissolved in it.* *Round your answer to 1 significant digit.* **Solution Explanation:** To solve for the final molarity of the iodide anion, follow these steps: 1. **Determine the moles of iron(II) iodide (FeI₂):** - Molar mass of FeI₂ = Fe (55.85 g/mol) + 2 * I (126.90 g/mol) = 309.65 g/mol - Moles of FeI₂ = mass (35.7 g) / molar mass (309.65 g/mol) 2. **Calculate the moles of iodide ions (I⁻) produced:** - Each mole of FeI₂ produces 2 moles of I⁻. - Moles of I⁻ = moles of FeI₂ * 2 3. **Assumption and Conversion:** - The total volume of the solution remains 350 mL (0.350 L). 4. **Determine the final molarity of the iodide ions:** - Final molarity (M) = moles of I⁻ / total volume in liters (L) **Diagram or Graph Explanation:** This problem does not include any diagrams or graphs. It only involves numerical calculations to determine the molarity of iodide anions in a given solution. **Interactive Tools:** On the user interface, several interactive buttons are visible: - A box to input the answer with units for molarity (M). - Buttons likely for submission ("X" for cancel, a reset button, and a help button). **Important Points to Remember:** - Always account for significant digits in the final answer. - Pay close attention to the molar masses and conversion between grams and moles. - Consider the assumption that volume remains constant when solutes are added to a solution.
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