MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Question
Suppose 3 people click on a website advertisement per second. Let Y be # of people who click the advertisement in the next 2.4 seconds. Find P(Y > or = 10) The solution is 0.19 but I keep getting slightly less. Please explain how to do this. Here’s my solution
2. = 3 people 1₁ X= 3x2.414.4 pct₁ = 2.4 = 7.2 P(10)= P(10) = 7.20 é p(q) = 7.2 e P(4) 15 e PL8)= 2.20 10 -7.2 110486 C P(1) P(7) = 7.2 e 7' PL6) = 7.2 e Plo) -7.2 9! & -7.2 8! D(S)- 7.25.7.2 5! C 7 -7.2 -7.2 -7.2 1(3) = 2,2³²0² 7.2 e 41 3-7.2 P(2) = 7.2² e て 2: 7.21 21 2-7.2 1-22 = 72 é t₁ = 1/second = 0.077 = 0.1069 = 0.1333 = 0.1485 = 0.1444 01203 072 0.08 35 -0.84644 = 0.01935 and J.-2.4 Now = 0.00537 Sum all values G.8862 S ni) về 1-0.8862 = 0.0007465
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Transcribed Image Text:2. = 3 people 1₁ X= 3x2.414.4 pct₁ = 2.4 = 7.2 P(10)= P(10) = 7.20 é p(q) = 7.2 e P(4) 15 e PL8)= 2.20 10 -7.2 110486 C P(1) P(7) = 7.2 e 7' PL6) = 7.2 e Plo) -7.2 9! & -7.2 8! D(S)- 7.25.7.2 5! C 7 -7.2 -7.2 -7.2 1(3) = 2,2³²0² 7.2 e 41 3-7.2 P(2) = 7.2² e て 2: 7.21 21 2-7.2 1-22 = 72 é t₁ = 1/second = 0.077 = 0.1069 = 0.1333 = 0.1485 = 0.1444 01203 072 0.08 35 -0.84644 = 0.01935 and J.-2.4 Now = 0.00537 Sum all values G.8862 S ni) về 1-0.8862 = 0.0007465
Expert Solution
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Step 1

Given that:

Average number of successes in an interval of 1 second, λ=3

Length of time, t=2.4 seconds

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