Sulfur compounds are converted to H2S04 while NO, compounds are converted to H deposition involves different substances, one process that naturally occurs is nitrificat 3/mol, Mµ = 1.008 g/mol, Ms = 32.07 g/mol) NH + 202 → NG A. If 12.06 g of NH4* was found in the soil, how many ions of NH4* was presenti B. If 500 g of H2O was produced after nitrification, how many moles of H were co C. How many grams of O are found in 1.815 x 1024 atoms of NO3 was produced

2KMnO, +5Hg₂Cl₂ + 16HCl→ 10HgCl₂ + 2MnCl₂ + 2KCI+ 8H₂O Using the following data: Reaction: 472.09 1999 Molar mass (g/mol):158.0 Mass (g): 316.1 The excess reactant(s) would be: excess A. Only KMnO₁ B. KMnO, and HCI C. Only HCI D. KMnO, and Hg₂Cl₂ E. KMnO, and HCI

[References] a. An aqueous solution contains 3.45 g of iron(III) sulfate, Fe2 (SO4)3, per liter. What is the molarity of Fe2 (SO4)3 ? Molarity = M b. When the compound dissolves in water, the Fet ions and the SO4 ions in the crystal go into the solution. What is the molar concentration of each ion in the solution? Molar concentration = M Fe+ Molar concentration = M SO Submit Answer Try Another Version 6 item attempts remaining Visited Email l

2. 0.349 g of CaCl2•2H2O and 0.698 g of NazCO; are dissolved in 100 mL of water to form a solution. a. What is the limiting reactant? b. How many grams of CaCO; will precipitate? c. How many grams of the excess reactant remain after the reaction has gone to completion?

15. If 23.0 mL of a 1.00 M Ba(NO3)2 solution was reacted with 55.0 mL of a 0.700 M solution of K3PO4 to produce the solid Ba3(PO4)2 by the balanced chemical equation 3 Ba(NO3)2 (aq) + 2 K3PO4(aq) – Ba3(PO4)2(s) + 6 KNO3(aq) a. What is the limiting reagent? AS b. How many grams of Ba3(PO4)2 will be produced? elomibt.ESE -3HA

The mineral iron pyrite (FeS2), typically, has a mass percentage of what is known as fool’s gold of 90-95%. The actual percentage in a sample can be determined using gravimetric analysis. To find the % mass of FeS2 the sulphur in FeS2 is firstly converted to sulphate (SO42-). These sulphate ions (SO42-) is mixed with an excess of barium chloride (BaCl2) to form barium sulphate (BaSO4), according to the following reaction:                                     Ba2+(aq) + SO42- (aq) à BaSO4 (s) When the reaction has gone to completion, the BaSO4 precipitate is collected in a filter paper and carefully washed. The filter paper and its contents are then transferred to a crucible. The crucible and its contents are heated until constant mass is achieved. The data for the analysis of a mineral sample is shown in the table below:  Initial Mass of mineral sample 17.5 g Mass of crucible and filter paper 144.60 g Mass of crucible, filter paper and dry BaSO4 196.89 g Molar mass…