Successive posiions before collision Successive positions of m, after collision ViS 10. Consider the collision of a moving puck with a second, initially stationary puck, as shown in the figure. According to the law of conservation of momentum mjv1 = m¡Vif+ m2V2f where mj = 0.50 kg is the mass of the first puck with initial velocity vifand final m, before collision Successive positions of m2 after collision velocity v2f, and m2 = 0.60 kg is the mass of the second puck with outgoing velocity v2f. Assume the incoming velocity of the first puck is along the x-axis and the outgoing velocity of mass m is at angle 01 = 50°. Suppose the initial speed of mass mj is vi = 1.5 m/s and the final speed of mass m is vif=0.5 m/s. Mass m2 leaves at angle 02 with respect to the x-axis and you will need to find this angle as part of this problem. Part (a) What is the x-component of the momentum of mass mj before the collision? Give answer in kg m/s to two significant figures. Pox =
Successive posiions before collision Successive positions of m, after collision ViS 10. Consider the collision of a moving puck with a second, initially stationary puck, as shown in the figure. According to the law of conservation of momentum mjv1 = m¡Vif+ m2V2f where mj = 0.50 kg is the mass of the first puck with initial velocity vifand final m, before collision Successive positions of m2 after collision velocity v2f, and m2 = 0.60 kg is the mass of the second puck with outgoing velocity v2f. Assume the incoming velocity of the first puck is along the x-axis and the outgoing velocity of mass m is at angle 01 = 50°. Suppose the initial speed of mass mj is vi = 1.5 m/s and the final speed of mass m is vif=0.5 m/s. Mass m2 leaves at angle 02 with respect to the x-axis and you will need to find this angle as part of this problem. Part (a) What is the x-component of the momentum of mass mj before the collision? Give answer in kg m/s to two significant figures. Pox =
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Transcribed Image Text:Successive positions of m,.
before collision
Successive positions of m,
after collision
Vis
Consider the collision of a moving puck with a second, initially stationary puck,
as shown in the figure. According to the law of conservation of momentum
2+ vןmmyvy =
where mj = 0.50 kg is the mass of the first puck with initial velocity vif and final
velocity v2f, and m2 = 0.60 kg is the mass of the second puck with outgoing
velocity v2f. Assume the incoming velocity of the first puck is along the x-axis
and the outgoing velocity of mass mj is at angle 01 = 50°. Suppose the initial
speed of mass mj is vi = 1.5 m/s and the final speed of mass mj is vif=0.5 m/s.
Mass m2 leaves at angle 02 with respect to the x-axis and you will need to find
this angle as part of this problem.
m, before collision
Successive positions of m,
after collision
Part (a) What is the x-component of the momentum of mass m¡ before the collision? Give answer in kg m/s to two significant figures.
Pox =
sin()
cos()
tan()
8
9
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cotan()
asin()
acos()
EAA
4.
6.
atan()
acotan() (
sinh()
1
3
cosho
tanh)
otonh0
Transcribed Image Text:Part (b) What is the y-component of the momentum of mass m, before the collision? Give answer in kg m/s to two digits.
Part (c) What is the x-component of the momentum of mass m, after the collision? Give answer in kg m/s to two digits.
Part (d) What is the y-component of the momentum of mass mj after the collision? Give answer in kg m/s to two digits.
Part (e) What is the x-component of the momentum of mass m2 after the collision? Give answer in kg m/s to two digits.
Part (f) What is the y-component of the momentum of mass m2 after the collision? Give answer in kg m/s to two digits.
Part (g) What is the angle 02 in degrees? If the mass m2 goes as shown in the diagram (below the x-axis) assign a negative value to the angle 02,
while if the mass m2 goes above the x-axis assign a positive value to 02. Give answer in degrees to two significant figures.
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