Students launch a steel ball horizontally from a tabletop. The initial horizontal speed of the ball is v, the tabletop height above the floor is H. The objective is to get steel ball into the coffee can of height h. Calculate the distance D at which the students need to place the can to make a "bulls-eye". v = 6 m/s H = 7 m h = 0.17 m %3D

Catherine can throw a cricket ball at 17 m/s. At what angle (to the nearest degree) to the horizontal must she throw the ball to hit a target 25 m away (ignore Catherine’s height)? A)He cannot hit the target whatever angle he throws at B) There is one and only one angle that he can throw the ball at and that is 29 degrees (с ) There is one and only one angle that he can throw the ball at and that is 61 degrees (D) There are two possible angles: he can throw the ball at either 29 degrees or 61 degrees

A daredevil is shot out of a cannon at 45.0° to the horizontal with an initial speed of 28.5 m/s. A net is positioned a horizontal distance of 52.5 m from the cannon. At what height above the cannon should the net be placed in order to catch the daredevil? m

I I6 PART B A player hits a tennis ball into the air with a velocity of 10 m/s at an angle of 60° to the horizontal. i) What was the initial horizontal velocity of the ball? i) What was the initial vertical velocity of the ball? (g = 9.8 m/s) U = initial velocity: Ux initial horizontal velocity Uy = initial vertical velocity Note: Ux = Ucose Uy = Usine %3D 9ME