Strength of intermolecular forces: Dispersion Forces < Dipole-Dipole < Hydrogen Bonding < Ion-Dipole 6. Which of the following intermolecular forces do all atoms have? a. Dispersion Forces b. Dipole-Dipole c. Hydrogen Bonding d. Ion-Dipole Forces 7. Which intermolecular force would be strongest if you dissolved Nal, sodium iodide, in water (which is polar)? a. Dispersion Forces (b. Dipole-Dipole c. Hydrogen Bonding d. Ion-Dipole Forces 8. Use your knowledge of electronegativity, polarity, and intermolecular forces to decide which of the following molecules would have the highest boiling point (requires the most energy input to make it evaporate into a gas). нн H. H-C-Ċ-H H-CI: H-C-H H. d. нн b. C. a. ELECTRONEGATIVITY Не H 2,1 n. B N Ne u Be 1,0 1,6 Na Mg 2,0 2,5 3,0 354.0 a Ar Al SI P. 1,5 1,8 2,1 2,5 3,0 Se Br 0,9 1,2 Kr Sc TI Cr Mn Fe Co NI Cu Zn Ga Ge As K Ca V. 0,8 1,0 1,3 1,5 1,6 1,6 1,5 1,8 1,9 1,9 1,9 1,6 1,6 1,8 2,0 2,4 2,8 1. Te Rh Pd Ag In Sn Sb Xe Sr Nb Mo Tc Ru Cd Rb Y Zr 0,8 1,0 1,2 14 1,6 1,8 1,9 2,2 2,2 2,2 1,9 1,7| 1,7 1,8 1,9 2,1 2,5 Bi Po At Rn W Re Os Pt Au Hg TI Pb fs Ba Hf Та Ir La 0,7 0,9 1,0 1,3 1,5 1,7 1,9 2,2 2,2 2,2 2,4 1,9 1,8 1,9 1,9 2,0 2,1 low medium high Bond Type Difference in Electronegativity 0.0 0.4 0.5 1.9 > 1.9 Non-polar covalent bond Polar covalent bond Ionic Bond
States of Matter
The substance that constitutes everything in the universe is known as matter. Matter comprises atoms which in turn are composed of electrons, protons, and neutrons. Different atoms combine together to give rise to molecules that act as a foundation for all kinds of substances. There are five states of matter based on their energies of attraction, namely solid, liquid, gases, plasma, and BEC (Bose-Einstein condensates).
Chemical Reactions and Equations
When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained using a chemical equation.
Step by step
Solved in 3 steps with 3 images