Straight-chain, saturated carboxylic acids, a class of hydrocarbons, has the general formula CH20+1COOH where n is an integerthan ranges from 1 to 18. What would be the %C by mass if n = 6 ?Atomic weights: C=12.01, H=1.01, O=15.99.Input values only with 2 decimal places. Do not include the units.Add your answer

Given is saturated carboxylic acid CnH2n+1COOH. With n = 6 Atomic weights as C = 12.01 g H = 1.01 g…

Answered: Straight-chain, saturated carboxylic…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Balance the following chemical equation and determine the number of moles of Fe(s) produced when 1 moles of Fe203(s) react with excess C(s) to produce Fe(s) and CO2(g). Fe203(s) + C(s) → Fe(s) + CO2(g) O Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 105)
How many formula units are in 30.912 g of potassium permanganate? Give answer to the correct number of significant figures. If exponents are needed, use the format 1.23E+4. Do not include unit or substance for this answer.
2) Calculate the %Yield of the 4 fractions based on the following numbers. Compare these numbers with your optical result (inspection of the amount of material on the bottom of each Erlenmeyer flask). Crude fraction from 1 egg 1.28g %Yield Fraction 1 0.3 g Fraction 2 0.42 8 Fraction 3 0.41 8 Fraction 4 0.12 g
(please type answer)
Calculate the following to the proper significant figures: The molecular mass of iron(II) hydroxide. The number of moles in 145g of MgCl2 The volume of 25.0g of steam at STP(steam is gaseous water) The concentration of a solution of table salt (NaCl) if 12g is dissolved in 1.5L of water
a) first box is it n=MxV or n=MxV/1000 or n=M+V or n=M+V/1000 or n=V+M or n=V+M/1000 second box is it 0.001 or 0.268 or 3.732 or 0.837 or 3731.524 or 0.000 third box is it Unit = g/mol or L or mL or atoms or mol/L or g or molecules b) first box is it 1.674x0.474 or 1.674x(0.674-0.474) or 1.674x(0.674+0.474)or 1.674x0.674 or 1.674-(0.674+0.474)second box is it = 0.793 or 1.459 or 1.128 or 0.335 or 8.371 or 1.921 the third box is it g/mol or L or mL or atoms or mol/L or g or molecules
A chemist adds 125.0 mL of a 0.183M potassium dichromate (K,Cr,O,) solution to a reaction flask. Calculate the mass in grams of potassium dichromate the chemist has added to the flask. Be sure your answer has the correct number of significant digits. x10
1:44 1 Send a chat Click in the answer box to activate the palette. Leaded gasoline contains an additive to prevent engine knocking. On analysis, the additive compound is found to contain carbon, hydrogen, and lead (Pb) (hence, leaded gasoline). When 51.36 g of this compound is burned in a combustion analysis apparatus, 55.90 g of CO2 and 28.61 g of H,0 are produced. Determine the empirical formula of the gasoline additive.
dadad A 3.82-g sample of magnesium nitride is reacted with 7.73 g of water. Mg3N2 + 3H2O → 2NH3 + 3MgO The yield of MgO is 3.73 g. What is the percent yield in the reaction? Atomic weights: Mg=24.31, N=14.01, H=1.01, O=15.99. Input values only with 2 decimal places.
A standard acid was prepared by placing 5.98 grams of H2C2O42H2O (molar mass: 126.07 g/mole) into a 250.00-milliliter volumetric flask. H2C2O4 (molar mass: 90.04 g/mole) For the blanks in this question: Report here only your numerical answers (without units), if the value is less than zero as a decimal (not in scientific notation), to the correct number of significant figures. Calculate the moles of H2C2O4 in the flask. Calculate the grams H2C2O4 in the flask. Calculate the molarity of the solution if the volumetric flask is filled to the mark with water.
A 3.82-g sample of magnesium nitride is reacted with 7.73 g of water. Mg3N2 + 3H20 2NH3 + 3MGO The yield of Mgo is 3.47 g. What is the percent yield in the reaction? Atomic weights: Mg=24.31, N=14.01, H=1.01, 0-15.99. Input values only with 2 decimal places.
In this experiment you will use a 3.0 x 10–5 M stock solution of red dye. 3.0 x 10–5 M means that the solution contains 3.0 x 10–5 moles of dye in one liter of solution. How many moles of dye molecules are in 2.0 mL of the 3.0 x 10–5 M stock solution?Express your answer to 2 significant figures

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