STOICHIOMETRY OF HEAT T02/S01 Solid urea reacts according to the balanced equation. When 9.58 mol of CO(NH2)2 is reacted, calculate the sign and magnitude (kJ) of the heat produced. Express your answer in scientific notation. Enthalpy_(kJ). 2 CO(NH2)2(s) + 3 02(g) - 2 N2(g) + 2 CO2(g) + 4 H20(1) . AH = -1268.6 Molar Mass CO(NH2)2 60.056 31.999 x 10 O2 N2 kJ 28.013 CO, 44.001 H20 18.015 Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER

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STOICHIOMETRY OF HEAT T02/S01
Solid urea reacts according to the balanced equation. When 9.58 mol of CO(NH2)2 is reacted, calculate the sign and magnitude (kJ) of the heat produced.
Express your answer in scientific notation.
Enthalpy_(kJ).
2 CO(NH2)2(s) + 3 02(g) - 2 N2(g) + 2 CO2(g) + 4 H20(1) .
AH = -1268.6
Molar Mass
CO(NH2)2
60.056
31.999
x 10
O2
N2
kJ
28.013
CO,
44.001
H20
18.015
Question Attempts: 0 of 1 used
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SAVE FOR LATER
Transcribed Image Text:STOICHIOMETRY OF HEAT T02/S01 Solid urea reacts according to the balanced equation. When 9.58 mol of CO(NH2)2 is reacted, calculate the sign and magnitude (kJ) of the heat produced. Express your answer in scientific notation. Enthalpy_(kJ). 2 CO(NH2)2(s) + 3 02(g) - 2 N2(g) + 2 CO2(g) + 4 H20(1) . AH = -1268.6 Molar Mass CO(NH2)2 60.056 31.999 x 10 O2 N2 kJ 28.013 CO, 44.001 H20 18.015 Question Attempts: 0 of 1 used SUBMIT ANSWER SAVE FOR LATER
Expert Solution
Step 1

Given,

Moles of CO(NH2)2 = 9.58 mol

 

For the reaction :

2 CO(NH2)2 (s) + 3 O2 (g) → 2 N2 (g) + 2 CO2 (g) + 4 H2O (l)

△H = –1268.6 kJ

Step 2

The heat produced when 9.58 mol of CO(NH2)2 reacts can be calculated as :

Chemistry homework question answer, step 2, image 1

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